springboot项目需要读取非application.yml/properties 的配置文件

news2024/11/14 13:31:35

1、操作步骤

1.新建配置文件：
在这里插入图片描述
2.编辑配置文件：

test-server=rd-dev02.jr.rong360.com

3.新建Config类：

@Component
@PropertySource(value = "kirara.properties")
public class KiraraConfig {

    @Value("${test-server:rd-dev02.jr.rong360.com}")
    private String testServer;

    public String getTestServer() {
        return testServer;
    }

    public void setTestServer(String testServer) {
        this.testServer = testServer;
    }
}

4.编辑调用类：

@RestController
public class UuapLoginController {

    @Autowired
    private UuapLoginService loginService;
    
    @Autowired
    private KiraraConfig kiraraConfig;

    /**
     * 登录方法
     *
     * @param loginBody 登录信息
     * @return 结果
     */
    @PostMapping("/api/v1/login")

    public AjaxResult login() throws Exception
    {
        AjaxResult ajax = AjaxResult.success();
        kiraraConfig.getTestServer();
        return ajax;
    }
}

2、总结

主要是用Config类去加载配置文件内容，然后注入到类中进行使用。

3、扩展

Spring中加载ApplicationContext.xml的方法分享，如下所示:

spring 中加载xml配置文件的方式有4种,分别为：
XmlBeanFactory,
ClassPathXmlApplicationContext,
FileSystemXmlApplicationContext,
XmlWebApplicationContext

扩展详情

4、第二种方法获取配置文件bean

1.配置实体类：

/**
 * 学生实体类
 * Created by ASUS on 2018/5/4
 */
 
@Component("Student")
public class Student {
    private String name;
    private  int age;
 
    public String getName() {
        return name;
    }
 
    public void setName(String name) {
        this.name = name;
    }
 
    public int getAge() {
        return age;
    }
 
    public void setAge(int age) {
        this.age = age;
    }
 
    public Student(String name, int age) {
        this.name = name;
        this.age = age;
    }
 
    public Student() {
    }
 
    @Override
    public String toString() {
        return "Student{" +
                "name='" + name + '\'' +
                ", age=" + age +
                '}';
    }
}

2.启动类配置：

/**
 * springboot启动类
 *
 */
 
@SpringBootApplication
//读取resources目录下的applicationContext.xml
@ImportResource("classpath:applicationContext.xml")
public class Application
{
    public static void main( String[] args )
    {
        ApplicationContext applicationContext= SpringApplication.run(Application.class,args);
        Student student= (Student) applicationContext.getBean("student",Student.class);
        System.out.println("message:"+student.toString());
 
    }
 
 
}

3.application.xml的内容：

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/beans
                   http://www.springframework.org/schema/beans/spring-beans-4.0.xsd
                   http://www.springframework.org/schema/context
                   http://www.springframework.org/schema/context/spring-context-4.0.xsd  ">
    <bean name="student" class="springboot.entity.Student">
        <property name="name" value="小黄"/>
        <property name="age" value="19"/>
    </bean>
 
 
</beans>