搜索与图论:有向图的拓扑序列
- 题目描述
- 参考代码
题目描述
输入样例
3 3
1 2
2 3
1 3
输出样例
···
1 2 3
···
参考代码
#include <cstring>
#include <iostream>
#include <algorithm>
using namespace std;
const int N = 100010;
int n, m;
int h[N], e[N], ne[N], idx;
int d[N], q[N];
void add(int a, int b)
{
e[idx] = b, ne[idx] = h[a], h[a] = idx++;
}
bool topsort()
{
int hh = 0, tt = -1;
for (int i = 1; i <= n; i++)
if (!d[i])
q[++tt] = i;
while (hh <= tt)
{
int t = q[hh ++];
for (int i = h[t]; i != -1; i = ne[i])
{
int j = e[i];
d[j]--;
if (d[j] == 0) q[++ tt] = j;
}
}
return tt == n - 1;
}
int main()
{
cin >> n >> m;
memset(h, -1, sizeof h);
for (int i = 0; i < m; i++)
{
int a, b;
cin >> a >> b;
add(a, b);
d[b]++;
}
if (topsort())
{
for (int i = 0; i < n; i++) printf("%d ", q[i]);
puts("");
}
else puts("-1");
return 0;
}