'''
思路：
定义一个函数，使用open函数，将文本内容打开。
定义一个空字典和空列表，进行循环及条件判断操作
'''
def count_word(file_path):
		dict_data = {}			#定义一个空字典
		f = open(file_path,"r",encoding="UTF-8")
		list_data = f.read()
		list_data = list_data.split()		#默认是空格为分隔符

		for i in list_data:
				if i in dict_data:
						dict_data[i] += 1
				else:
						dict_data[i] = 1
		f.close()

		while True:
			word = input("please input your word(input 'q' or 'Q'):")
			if word == 'Q' or word == 'q':
				print("Bye~")
				break
			if dict_data.get(word) == None:
				print(f"{word}'s count is 0")
				break
			else:
				print(f"{word}'s count is {dict_data.get(word)}")
		

count_word("C:/1.txt")

效果图：

利用PySpark第三方库，进行统计（人机交互暂未编写）：

# 1.构建执行环境入口对象
from pyspark import SparkContext,SparkConf
import os 
os.environ['PYSPARK_PYTHON'] = "python.exe文件位置"
conf = SparkConf().setMaster("local[*]").setAppName("test_spark")
sc = SparkContext(conf = conf)

# 2.读取数据文件
rdd = sc.textFile("C:/1.txt")

# 3.获取全部单词,默认以空格为分隔符
word_rdd = rdd.flatMap(lambda x:x.split(" "))

# 4.将单词转换为二元元祖
word_withone_add = word_rdd.map(lambda word:(word,1))

# 5.分组求和
result_add = word_withone_add.reduceByKey(lambda a,b:a+b)

# 6.打印出结果
print(result_add.collect())