文章目录
- 一、拉格朗日松弛
- 二、次梯度算法
- 三、案例实战
一、拉格朗日松弛
当遇到一些很难求解的模型,但又不需要去求解它的精确解,只需要给出一个次优解或者解的上下界,这时便可以考虑采用松弛模型的方法加以求解。
对于一个整数规划问题,拉格朗日松弛放松模型中的部分约束。这些被松弛的约束并不是被完全去掉,而是利用拉格朗日乘子在目标函数上增加相应的惩罚项,对不满足这些约束条件的解进行惩罚。
拉格朗日松弛之所以受关注,是因为在大规模的组合优化问题中,若能在原问题中减少一些造成问题“难”的约束,则可使问题求解难度大大降低,有时甚至可以得到比线性松弛更好的上下界。
二、次梯度算法
由于拉格朗日对偶问题通常是分段线性的,这会导致其在某些段上不可导,所以没法使用常规的梯度下降法处理。于是引入次梯度(Subgradient)用于解决此类目标函数并不总是处处可导的问题。
次梯度算法的优势是比传统方法能够处理的问题范围更大,不足之处就是算法收敛速度慢。
三、案例实战
松弛之后的目标函数为
m a x : z = 16 x 1 + 10 x 2 + 4 x 4 + μ [ 10 − ( 8 x 1 + 2 x 2 + x 3 + 4 x 4 ) ] max :z=16x_1+10x_2+4x_4+\mu[10-(8x_1+2x_2+x_3+4x_4)] max:z=16x1+10x2+4x4+μ[10−(8x1+2x2+x3+4x4)]
化简为
m a x : z = ( 16 − 8 μ ) x 1 + ( 10 − 2 μ ) x 2 + ( − μ ) x 3 + ( 4 − 4 μ ) x 4 + 10 μ max :z=(16-8\mu)x_1+(10-2\mu)x_2+(-\mu)x_3+(4-4\mu)x_4+10\mu max:z=(16−8μ)x1+(10−2μ)x2+(−μ)x3+(4−4μ)x4+10μ
由于每一次迭代时 μ \mu μ 是一个确定的常数,所以目标函数中的 10 μ 10\mu 10μ 可以在建模时省略
具体求解代码如下:
import ilog.concert.IloException;
import ilog.concert.IloIntVar;
import ilog.concert.IloLinearNumExpr;
import ilog.cplex.IloCplex;
import java.util.Arrays;
public class TestLR {
// lambda
static double lambda = 2d;
// 最大迭代次数
static int epochs = 100;
// 上界最大未更新次数
static int ubMaxNonImproveCnt = 3;
// 最小步长
static double minStep = 0.001;
// 松弛问题模型
static IloCplex relaxProblemModel;
// 变量数组
static IloIntVar[] intVars;
// 最佳上下界
static double bestLB = 0d;
static double bestUB = 1e10;
// 最佳拉格朗日乘数
static double bestMu = 0d;
// 最佳解
static double[] bestX;
// 运行主函数
public static void run() throws IloException {
//
double mu = 0d;
double step = 1d;
int ubNonImproveCnt = 0;
// 初始化松弛问题模型
initRelaxModel();
// 开始迭代
for (int epoch = 0; epoch < epochs; epoch++) {
System.out.println("----------------------------- Epoch-" + (epoch + 1) + " -----------------------------");
System.out.println("mu: " + mu);
System.out.println("lambda: " + lambda);
// 根据mu,设置松弛问题模型目标函数
setRelaxModelObjectiveBuMu(mu);
if (relaxProblemModel.solve()) {
// 获得当前上界(由于建模时没有考虑常数 10*mu,所以这里要加回来,得到松弛问题的真正目标值)
double curUB = relaxProblemModel.getObjValue() + 10 * mu;
// 更新上界
if (curUB < bestUB) {
bestUB = curUB;
ubNonImproveCnt = 0;
} else {
ubNonImproveCnt++;
}
System.out.println("curUB: " + curUB);
// 获取变量值
double[] x = relaxProblemModel.getValues(intVars);
// 计算次梯度
double subGradient = (8 * x[0] + 2 * x[1] + x[2] + 4 * x[3]) - 10;
double dist = Math.pow(subGradient, 2);
// 迭迭代停止条件1
if (dist <= 0.0) {
System.out.println("Early stop: dist (" + dist + ") <= 0 !");
break;
}
// 如果次梯度大于等于0,说明满足被松弛的约束,即可以作为原问题的可行解
if (subGradient <= 0) {
// 计算当前原问题的解值
double obj = 16 * x[0] + 10 * x[1] + 4 * x[3];
if (obj > bestLB) {
// 更新下界
bestLB = obj;
bestMu = mu;
bestX = x.clone();
}
}
System.out.println("subGradient: " + subGradient);
System.out.println("bestUB: " + bestUB);
System.out.println("bestLB: " + bestLB);
System.out.println("gap: " + String.format("%.2f", (bestUB - bestLB) * 100d / bestUB) + " %");
// 迭代停止条件2
if (bestLB >= bestUB - 1e-06) {
System.out.println("Early stop: bestLB (" + bestLB + ") >= bestUB (" + bestUB + ") !");
break;
}
// 上界未更新达到一定次数
if (ubNonImproveCnt >= ubMaxNonImproveCnt) {
lambda /= 2;
ubNonImproveCnt = 0;
}
// 更新拉格朗日乘数
mu = Math.max(0, mu + step * subGradient);
// 更新步长
step = lambda * (curUB - bestLB) / dist;
// 迭代停止条件3
if (step < minStep) {
System.out.println("Early stop: step (" + step + ") is less than minStep (" + minStep + ") !");
break;
}
} else {
System.err.println("Lagrange relaxation problem has no solution!");
}
}
}
// 建立松弛问题模型
private static void initRelaxModel() throws IloException {
relaxProblemModel = new IloCplex();
relaxProblemModel.setOut(null);
// 声明4个整数变量
intVars = relaxProblemModel.intVarArray(4, 0, 1);
// 添加约束
// 约束1:x1+x2<=1
relaxProblemModel.addLe(relaxProblemModel.sum(intVars[0], intVars[1]), 1);
// 约束2:x3+x4<=1
relaxProblemModel.addLe(relaxProblemModel.sum(intVars[2], intVars[3]), 1);
}
// 根据mu,设置松弛问题模型的目标函数
private static void setRelaxModelObjectiveBuMu(double mu) throws IloException {
// 目标函数(省略了常数 10*mu)
IloLinearNumExpr target = relaxProblemModel.linearNumExpr();
target.addTerm(16 - 8 * mu, intVars[0]);
target.addTerm(10 - 2 * mu, intVars[1]);
target.addTerm(0 - mu, intVars[2]);
target.addTerm(4 - 4 * mu, intVars[3]);
if (relaxProblemModel.getObjective() == null) {
relaxProblemModel.addMaximize(target);
} else {
relaxProblemModel.getObjective().setExpr(target);
}
}
public static void main(String[] args) throws IloException {
long s = System.currentTimeMillis();
run();
System.out.println("----------------------------- Solution -----------------------------");
System.out.println("bestMu: " + bestMu);
System.out.println("bestUB: " + bestUB);
System.out.println("bestLB: " + bestLB);
System.out.println("gap: " + String.format("%.2f", (bestUB - bestLB) * 100d / bestUB) + " %");
System.out.println("bestX: " + Arrays.toString(bestX));
System.out.println("Solve Time: " + (System.currentTimeMillis() - s) + " ms");
}
}
程序输出:
----------------------------- Epoch-1 -----------------------------
mu: 0.0
lambda: 2.0
curUB: 20.0
subGradient: 2.0
bestUB: 20.0
bestLB: 0.0
gap: 100.00 %
----------------------------- Epoch-2 -----------------------------
mu: 2.0
lambda: 2.0
curUB: 26.0
subGradient: -8.0
bestUB: 20.0
bestLB: 10.0
gap: 50.00 %
----------------------------- Epoch-3 -----------------------------
mu: 0.0
lambda: 2.0
curUB: 20.0
subGradient: 2.0
bestUB: 20.0
bestLB: 10.0
gap: 50.00 %
----------------------------- Epoch-4 -----------------------------
mu: 1.0
lambda: 2.0
curUB: 18.0
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-5 -----------------------------
mu: 11.0
lambda: 2.0
curUB: 110.0
subGradient: -10.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-6 -----------------------------
mu: 0.0
lambda: 2.0
curUB: 20.0
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-7 -----------------------------
mu: 4.0
lambda: 2.0
curUB: 42.0
subGradient: -8.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-8 -----------------------------
mu: 0.0
lambda: 1.0
curUB: 20.0
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-9 -----------------------------
mu: 1.0
lambda: 1.0
curUB: 18.0
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-10 -----------------------------
mu: 6.0
lambda: 1.0
curUB: 60.0
subGradient: -10.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-11 -----------------------------
mu: 0.0
lambda: 0.5
curUB: 20.0
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-12 -----------------------------
mu: 0.5
lambda: 0.5
curUB: 19.0
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-13 -----------------------------
mu: 3.0
lambda: 0.5
curUB: 34.0
subGradient: -8.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-14 -----------------------------
mu: 0.0
lambda: 0.25
curUB: 20.0
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-15 -----------------------------
mu: 0.1875
lambda: 0.25
curUB: 19.625
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-16 -----------------------------
mu: 1.4375
lambda: 0.25
curUB: 21.5
subGradient: -8.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-17 -----------------------------
mu: 0.0
lambda: 0.125
curUB: 20.0
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-18 -----------------------------
mu: 0.044921875
lambda: 0.125
curUB: 19.91015625
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-19 -----------------------------
mu: 0.669921875
lambda: 0.125
curUB: 18.66015625
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-20 -----------------------------
mu: 1.289306640625
lambda: 0.0625
curUB: 20.314453125
subGradient: -8.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-21 -----------------------------
mu: 0.206787109375
lambda: 0.0625
curUB: 19.58642578125
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-22 -----------------------------
mu: 0.22693252563476562
lambda: 0.0625
curUB: 19.54613494873047
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-23 -----------------------------
mu: 0.5265083312988281
lambda: 0.03125
curUB: 18.946983337402344
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-24 -----------------------------
mu: 0.6756666898727417
lambda: 0.03125
curUB: 18.648666620254517
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-25 -----------------------------
mu: 0.8154633045196533
lambda: 0.03125
curUB: 18.369073390960693
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-26 -----------------------------
mu: 0.9505987204611301
lambda: 0.015625
curUB: 18.09880255907774
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-27 -----------------------------
mu: 1.0159821063280106
lambda: 0.015625
curUB: 18.127856850624084
subGradient: -8.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-28 -----------------------------
mu: 0.7628945263568312
lambda: 0.015625
curUB: 18.474210947286338
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-29 -----------------------------
mu: 0.766863206459675
lambda: 0.0078125
curUB: 18.46627358708065
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-30 -----------------------------
mu: 0.7999655929725122
lambda: 0.0078125
curUB: 18.400068814054976
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-31 -----------------------------
mu: 0.833036974172046
lambda: 0.0078125
curUB: 18.333926051655908
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-32 -----------------------------
mu: 0.8658497429769483
lambda: 0.00390625
curUB: 18.268300514046103
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-33 -----------------------------
mu: 0.8821269422965887
lambda: 0.00390625
curUB: 18.235746115406823
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-34 -----------------------------
mu: 0.8982759667380851
lambda: 0.00390625
curUB: 18.20344806652383
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-35 -----------------------------
mu: 0.914361408369739
lambda: 0.001953125
curUB: 18.17127718326052
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-36 -----------------------------
mu: 0.9223725881222037
lambda: 0.001953125
curUB: 18.155254823755595
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-37 -----------------------------
mu: 0.9303523509964815
lambda: 0.001953125
curUB: 18.13929529800704
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-38 -----------------------------
mu: 0.9383164670353054
lambda: 9.765625E-4
curUB: 18.123367065929386
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-39 -----------------------------
mu: 0.9422907323175354
lambda: 9.765625E-4
curUB: 18.11541853536493
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-40 -----------------------------
mu: 0.9462572201426962
lambda: 9.765625E-4
curUB: 18.107485559714608
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
Early stop: step (9.896832958635996E-4) is less than minStep (0.001) !
----------------------------- Solution -----------------------------
bestMu: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
bestX: [0.0, 1.0, 0.0, 0.0]
Solve Time: 152 ms
分析:
从最终结果可以看到, bestLB 为10,也就是通过拉格朗日松弛&次梯度算法得到的最优可行解的目标值为10,这明显不是最优解(最优解应该是16, x 1 = 1 x_1=1 x1=1,其余变量为0)
这是因为我们松弛了一个约束,所以通过拉格朗日松弛&次梯度算法得到的解不一定是最优解。但是当遇到一些很难求解的模型,但又不需要去求解它的精确解时,拉格朗日松弛&次梯度算法就可以派上用场了!
参考链接:
- 【凸优化笔记5】-次梯度方法(Subgradient method)
- 运筹学教学|快醒醒,你的熟人拉格朗日又来了!!
- 拉格朗日松弛求解整数规划浅析(附Python代码实例)