一、作业

完成算术运算符重载，实现至少两个运算符的成员函数和全局函数的版本

1.（1）成员函数实现算术运算符（-）重载

const 类名 operator#(const 类名 &R) const

{}

#include <iostream>

using namespace std;

class Person
{
private:
    int a;
    int b;
public:
    Person(){}
    Person(int a, int b):a(a),b(b)
    {

    }
    void show()
    {
        cout << "a = " << a << endl;
        cout << "b = " << b << endl;
    }
    const Person operator-(const Person &R) const
    {
        Person temp;
        temp.a = a - R.a;
        temp.b = b - R.b;
        return temp;
    }
};
int main()
{

   Person p1(30,20);
   Person p2(10,10);

   Person p3 = p1 - p2;
   p3.show();

    return 0;
}

（2）全局函数实现算术运算符（-）重载

const 类名 operator#(const 类名 &L, const 类名 &R)

{}

#include <iostream>

using namespace std;

class Person
{
    friend const Person operator-(const Person &L, const Person &R);
private:
    int a;
    int b;
public:
    Person(){}
    Person(int a, int b):a(a),b(b)
    {

    }
    void show()
    {
        cout << "a = " << a << endl;
        cout << "b = " << b << endl;
    }

};
const Person operator-(const Person &L, const Person &R)
{
    Person temp;
    temp.a = L.a - R.a;
    temp.b = L.b - R.b;
    return temp;
}
int main()
{

   Person p1(30,20);
   Person p2(10,10);

   Person p3 = p1 - p2;
   p3.show();

    return 0;
}

实现结果：

2.（1）成员函数实现算术运算符（*）重载

const 类名 operator#(const 类名 &R) const

{}

#include <iostream>

using namespace std;

class Person
{
private:
    int a;
    int b;
public:
    Person(){}
    Person(int a, int b):a(a),b(b)
    {

    }
    void show()
    {
        cout << "a = " << a << endl;
        cout << "b = " << b << endl;
    }
    const Person operator*(const Person &R) const
    {
        Person temp;
        temp.a = a * R.a;
        temp.b = b * R.b;
        return temp;
    }
};
int main()
{

   Person p1(3,2);
   Person p2(2,4);

   Person p3 = p1 * p2;
   p3.show();

    return 0;
}

（2）全局函数实现算术运算符（*）重载

const 类名 operator#(const 类名 &L, const 类名 &R)

{}

#include <iostream>

using namespace std;

class Person
{
    friend const Person operator*(const Person &L, const Person &R);
private:
    int a;
    int b;
public:
    Person(){}
    Person(int a, int b):a(a),b(b)
    {

    }
    void show()
    {
        cout << "a = " << a << endl;
        cout << "b = " << b << endl;
    }

};
const Person operator*(const Person &L, const Person &R)
{
    Person temp;
    temp.a = L.a * R.a;
    temp.b = L.b * R.b;
    return temp;
}
int main()
{

   Person p1(3,20);
   Person p2(10,10);

   Person p3 = p1 * p2;
   p3.show();

    return 0;
}

代码实现：

二、思维导图