solution

找末尾0的个数，即找有多少对2和5
==>问题等价于寻找所给数据中，有多少个2和5的因子，较少出现的因子次数即为0的个数

#include <iostream>
using namespace std;
int main()
{
  // 请在此输入您的代码
  printf("31");
  return 0;
}

#include<stdio.h>
#include<math.h>
typedef long long ll;
int main(){
	ll  x, two = 0, five = 0, ans = 0;
	for(int i = 0; i < 100; i++){
		scanf("%lld", &x);
		while(x % 2 == 0){
			two++;
			x /= 2;
		}
		while(x % 5 == 0){
			five++;
			x /= 5;
		}
	}
	if(two > five) two = five;
	printf("%lld", two);
	return 0;
}