//浮点数存储
int main()
{
	int n = 9;
	//00000000 00000000 00000000 00001001
	//0 00000000 00000000000000000001001
	//S  E(8bit)        M(23bit)
	//E=-126
	//M=0.000000000000000000001001
	//+ 0.000000000000000000001001 *2^-126
	float* pFloat = (float*)&n;
	printf("n的值为：%d\n", n);//9
	printf("*pFloat的值为：%f\n", *pFloat);//0.000000
	*pFloat = 9.0;
	//1001.0
	//1.001*2^3
	//S=0 E=3 M=1.001
	//0 10000010 00100000000000000000000  //这里的E(3+127=130  8bit) 
	//01000001000100000000000000000000

	printf("num的值为：%d\n", n);//1091567616   01000001000100000000000000000000
	printf("*pFloat的值为：%f\n", *pFloat);//9.000000
	return 0;
}

浮点数存储的公式