文章目录
- SQL136 每类试卷得分前3名
- 描述
- 示例1
- 输入：
- 输出：
- 答案
SQL136 每类试卷得分前3名
描述
现有试卷信息表examination_info（exam_id试卷ID, tag试卷类别, difficulty试卷难度, duration考试时长, release_time发布时间）：
| id | exam_id | tag | difficulty | duration | release_time |
|---|---|---|---|---|---|
| 1 | 9001 | SQL | hard | 60 | 2021-09-01 06:00:00 |
| 2 | 9002 | SQL | hard | 60 | 2021-09-01 06:00:00 |
| 3 | 9003 | 算法 | medium | 80 | 2021-09-01 10:00:00 |
试卷作答记录表exam_record（uid用户ID, exam_id试卷ID, start_time开始作答时间, submit_time交卷时间, score得分）：
| id | uid | exam_id | start_time | submit_time | score |
|---|---|---|---|---|---|
| 1 | 1001 | 9001 | 2021-09-01 09:01:01 | 2021-09-01 09:31:00 | 78 |
| 2 | 1002 | 9001 | 2021-09-01 09:01:01 | 2021-09-01 09:31:00 | 81 |
| 3 | 1002 | 9002 | 2021-09-01 12:01:01 | 2021-09-01 12:31:01 | 81 |
| 4 | 1003 | 9001 | 2021-09-01 19:01:01 | 2021-09-01 19:40:01 | 86 |
| 5 | 1003 | 9002 | 2021-09-01 12:01:01 | 2021-09-01 12:31:51 | 89 |
| 6 | 1004 | 9001 | 2021-09-01 19:01:01 | 2021-09-01 19:30:01 | 85 |
| 7 | 1005 | 9003 | 2021-09-01 12:01:01 | 2021-09-01 12:31:02 | 85 |
| 8 | 1006 | 9003 | 2021-09-07 10:01:01 | 2021-09-07 10:21:01 | 84 |
| 9 | 1003 | 9003 | 2021-09-08 12:01:01 | 2021-09-08 12:11:01 | 40 |
| 10 | 1003 | 9002 | 2021-09-01 14:01:01 | (NULL) | (NULL) |
找到每类试卷得分的前3名，如果两人最大分数相同，选择最小分数大者，如果还相同，选择uid大者。由示例数据结果输出如下：
| tid | uid | ranking |
|---|---|---|
| SQL | 1003 | 1 |
| SQL | 1004 | 2 |
| SQL | 1002 | 3 |
| 算法 | 1005 | 1 |
| 算法 | 1006 | 2 |
| 算法 | 1003 | 3 |
解释：有作答得分记录的试卷tag有SQL和算法，SQL试卷用户1001、1002、1003、1004有作答得分，最高得分分别为81、81、89、85，最低得分分别为78、81、86、40，因此先按最高得分排名再按最低得分排名取前三为1003、1004、1002。
示例1
输入：
drop table if exists examination_info,exam_record;
CREATE TABLE examination_info (
id int PRIMARY KEY AUTO_INCREMENT COMMENT '自增ID',
exam_id int UNIQUE NOT NULL COMMENT '试卷ID',
tag varchar(32) COMMENT '类别标签',
difficulty varchar(8) COMMENT '难度',
duration int NOT NULL COMMENT '时长',
release_time datetime COMMENT '发布时间'
)CHARACTER SET utf8 COLLATE utf8_general_ci;
CREATE TABLE exam_record (
id int PRIMARY KEY AUTO_INCREMENT COMMENT '自增ID',
uid int NOT NULL COMMENT '用户ID',
exam_id int NOT NULL COMMENT '试卷ID',
start_time datetime NOT NULL COMMENT '开始时间',
submit_time datetime COMMENT '提交时间',
score tinyint COMMENT '得分'
)CHARACTER SET utf8 COLLATE utf8_general_ci;
INSERT INTO examination_info(exam_id,tag,difficulty,duration,release_time) VALUES
(9001, 'SQL', 'hard', 60, '2021-09-01 06:00:00'),
(9002, 'SQL', 'hard', 60, '2021-09-01 06:00:00'),
(9003, '算法', 'medium', 80, '2021-09-01 10:00:00');
INSERT INTO exam_record(uid,exam_id,start_time,submit_time,score) VALUES
(1001, 9001, '2021-09-01 09:01:01', '2021-09-01 09:31:00', 78),
(1001, 9001, '2021-09-01 09:01:01', '2021-09-01 09:31:00', 81),
(1002, 9002, '2021-09-01 12:01:01', '2021-09-01 12:31:01', 81),
(1003, 9001, '2021-09-01 19:01:01', '2021-09-01 19:40:01', 86),
(1003, 9002, '2021-09-01 12:01:01', '2021-09-01 12:31:51', 89),
(1004, 9001, '2021-09-01 19:01:01', '2021-09-01 19:30:01', 85),
(1005, 9003, '2021-09-01 12:01:01', '2021-09-01 12:31:02', 85),
(1006, 9003, '2021-09-07 10:01:01', '2021-09-07 10:21:01', 84),
(1003, 9003, '2021-09-08 12:01:01', '2021-09-08 12:11:01', 40),
(1003, 9002, '2021-09-01 14:01:01', null, null);
输出：
SQL|1003|1
SQL|1004|2
SQL|1002|3
算法|1005|1
算法|1006|2
算法|1003|3
答案
SELECT tid,uid,ranking
FROM (SELECT ei.tag AS tid,uid,
ROW_NUMBER() OVER(PARTITION BY ei.tag ORDER BY max(er.score) DESC, min(er.score) DESC, er.uid DESC) AS ranking
FROM exam_record AS er
LEFT JOIN examination_info AS ei ON ei.exam_id = er.exam_id
GROUP BY ei.tag,er.uid) AS K
WHERE K.ranking <= 3;
