计算两个时间段的差值

运行效果：

代码实现：

#include<stdio.h>

typedef struct {
	int h;	//	时
	int m;	//	分
	int s;	//	秒
}Time;

void fun(Time T[2], Time& diff)
{
	int sum_s[2] = { 0 };		
	for (int i = 0; i <= 1; i++) {	// 统一为秒数
		sum_s[i] = T[i].h * 60 * 60 + T[i].m * 60 + T[i].s;
	}

	// 时差
	int diff_s = sum_s[0] >= sum_s[1] ? (sum_s[0] - sum_s[1]) : (sum_s[1] - sum_s[0]);
	diff.h = diff_s / (60 * 60);

	// 分差
	diff_s = diff_s % (60 * 60);
	diff.m = diff_s / 60;

	// 秒差
	diff_s = diff_s % 60;
	diff.s = diff_s;
}



int main()
{
	Time T[2];
	Time diff = {0};

	// 输入
	for (int i = 0; i <= 1; i++) {
		printf("请输入第%d个时间的小时：",i+1);
		scanf_s("%d", &T[i].h);
		printf("请输入第%d个时间的分钟：",i+1);
		scanf_s("%d", &T[i].m);
		printf("请输入第%d个时间的秒数：",i+1);
		scanf_s("%d", &T[i].s);
	}

	// 计算时间差
	fun(T, diff);

	// 输出
	for (int i = 0; i <= 1; i++) {
		printf("第%d个时间：%02d时%02d分%02d秒\n", i+1,T[i].h,T[i].m,T[i].s);
	}
	printf("相差时间:%02d时%02d分%02d秒\n", diff.h, diff.m, diff.s);

    return 0;
}