开头

大家好，我叫这是我58。

程序

#define _CRT_SECURE_NO_WARNINGS 1
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <Windows.h>
typedef struct T {
	int ix;
	int iy;
}T;
void printmaze(const char strmaze[11][11], T tarr[9]) {
	int ia = 0;
	int ib = 0;
	int ic = 0;
	char str[5] = "33";
	for (ia = 0; ia < 11; ia++) {
		for (ib = 0; ib < 11; ib++) {
			for (ic = 0; ic < 9; ic++) {
				if ('@' == strmaze[tarr[ic].ix][tarr[ic].iy] && tarr[ic].ix == ia && tarr[ic].iy == ib) {
					strcpy(str, "33;1");
					break;
				}
			}
			printf("\033[%sm%c\033[0m", 'G' == strmaze[ia][ib] ? "32;1" : '$' == strmaze[ia][ib] || '#' == strmaze[ia][ib] ? "33;1" : '@' == strmaze[ia][ib] ? str : "0", strmaze[ia][ib]);
			strcpy(str, "33");
		}
		printf("|\n");
	}
	printf("-----------@\n");
}
int main() {
	int i = 0;
	char ch = 0;
	T tarr[9] = { {0,3},{0,9},{3,1},{4,0},{5,1},{7,4},{7,5},{9,2},{10,2} };
	char strmaze[11][11] = {
		'P','@',' ','$','*',' ',' ',' ',' ','$','@',
		'*','*',' ',' ','*',' ',' ',' ',' ','@','@',
		' ',' ','*',' ','@',' ',' ','@',' ','@',' ',
		'@','$',' ','*','*','@','@','*',' ','*',' ',
		'$','@',' ',' ',' ',' ',' ','*','@','*',' ',
		'@','$',' ','@',' ',' ',' ','@','*','@',' ',
		' ',' ',' ',' ','*','*',' ',' ',' ',' ',' ',
		'@','*',' ','*','$','$','*',' ','*','@','*',
		' ',' ','*',' ','@',' ',' ','*',' ',' ',' ',
		' ',' ','$','@',' ',' ',' ','@','@',' ','#',
		' ',' ','$',' ',' ','@',' ','*',' ','#','G'
	};
	char strmazer[11][11] = { 0 };
	memcpy(strmazer, strmaze, sizeof strmaze);
	char* cp = &strmaze[0][0];
	char* cboxp = cp;
	printf("欢迎你来玩推\033[33m箱子\033[0m迷宫，在这个迷宫中，“P”是你，空格是你可以走的地方，“\033[32;1mG\033[0m”为\033[32;1m终点\033[0m，\033[33m箱子“@”\033[0m可以推，门“\033[33;1m#\033[0m”一般无法通行，但在“\033[33;1m$\033[33;1m”全被\033[33m箱子“@”\033[0m占的时候，它们就会被打开，而且打开的时候所有的箱子“\033[33m@\033[0m”都会变成墙“*”，并且输入“r”即可重置迷宫，而你只要走到\033[32;1m终点\033[0m，就可以\033[32;1m赢\033[0m了，现在你听懂了吗?");
	Sleep(8000);
	system("cls");
	while ('G' == strmaze[10][10]) {
		int ifl = 0;
		printmaze(strmaze, tarr);
		scanf("%c", &ch);
		while ('\n' != getchar()) {
			;
		}
		*cp = ' ';
		switch (ch) {
		case 'w':
			for (i = 0; i < 11; i++) {
				if (cp == &strmaze[0][i]) {
					break;
				}
			}
			11 == i && '*' != *(cp - 11) && '#' != *(cp - 11) && '@' != *(cp - 11) && (cp -= 11, ifl = 1);
			if (!ifl && 11 == i && '@' == *(cp - 11)) {
				cboxp = cp - 11;
				(cboxp - &strmaze[0][0]) / 11 && (' ' == *(cboxp - 11) || '$' == *(cboxp - 11) ) && (*cboxp = ' ', cboxp -= 11, *cboxp = '@', cp -= 11);
			}
			break;
		case 'a':
			for (i = 0; i < 11; i++) {
				if (cp == &strmaze[i][0]) {
					break;
				}
			}
			11 == i && '*' != *(cp - 1) && '#' != *(cp - 1) && '@' != *(cp - 1) && (cp--, ifl = 1);
			if (!ifl && 11 == i && '@' == *(cp - 1)) {
				cboxp = cp - 1;
				(cboxp - &strmaze[0][0]) % 11 && (' ' == *(cboxp - 1) || '$' == *(cboxp - 1)) && (*cboxp-- = ' ', *cboxp = '@', cp--);
			}
			break;
		case 's':
			for (i = 0; i < 11; i++) {
				if (cp == &strmaze[10][i]) {
					break;
				}
			}
			11 == i && '*' != *(cp + 11) && '#' != *(cp + 11) && '@' != *(cp + 11) && (cp += 11, ifl = 1);
			if (!ifl && 11 == i && '@' == *(cp + 11)) {
				cboxp = cp + 11;
				10 != (cboxp - &strmaze[0][0]) / 11 && (' ' == *(cboxp + 11) || '$' == *(cboxp + 11)) && (*cboxp = ' ', cboxp += 11, *cboxp = '@', cp += 11);
			}
			break;
		case 'd':
			for (i = 0; i < 11; i++) {
				if (cp == &strmaze[i][10]) {
					break;
				}
			}
			11 == i && '*' != *(cp + 1) && '#' != *(cp + 1) && '@' != *(cp + 1) && (cp++, ifl = 1);
			if (!ifl && 11 == i && '@' == *(cp + 1)) {
				cboxp = cp + 1;
				10 != (cboxp - &strmaze[0][0]) % 11 && (' ' == *(cboxp + 1) || '$' == *(cboxp + 1)) && (*cboxp++ = ' ', *cboxp = '@', cp++);
			}
			break;
		case 'r':
			memcpy(strmaze, strmazer, sizeof strmaze);
			cp = &strmaze[0][0];
			cboxp = cp;
			break;
		default:
			break;
		}
		*cp = 'P';
		system("cls");
		for (ifl = 0, i = 0; i < 9; i++) {
			' ' == strmaze[tarr[i].ix][tarr[i].iy] && (strmaze[tarr[i].ix][tarr[i].iy] = '$');
			'@' == strmaze[tarr[i].ix][tarr[i].iy] && ifl++;
		}
		if (9 == ifl) {
			strmaze[9][10] = ' ';
			strmaze[10][9] = ' ';
			for (i = 0; i < 121; i++) {
				'@' == strmaze[0][i] && (strmaze[0][i] = '*');
			}
		}
	}
	system("color 0A");
	printf("恭喜你，你赢了\n");
	return 0;
}

程序的流程图

程序游玩的效果

下一篇博客要说的东西

C语言中的#和##