目录
- 开头
- 程序
- 程序的流程图
- 程序游玩的效果
- 下一篇博客要说的东西
开头
大家好,我叫这是我58。
程序
#define _CRT_SECURE_NO_WARNINGS 1
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <Windows.h>
enum WASD {
W,
A,
S,
D
};
enum YYSe{
YI,
YA,
SW,
N
};
typedef struct YYS {
enum YYSe yy;
int ix;
int iy;
}YYS;
void printmaze(const char strmaze[11][11], const int iyi, const int iya, const int iyy) {
int ia = 0;
int ib = 0;
for (ia = 0; ia < 11; ia++) {
for (ib = 0; ib < 11; ib++) {
printf("\033[%s%sm%c\033[0m", 'G' == strmaze[ia][ib] ? "32;1" : "0", iyy % 2 ? ";7" : "", strmaze[ia][ib]);
}
printf("\033[%cm|\033[0m\n", iyy % 2 ? '7' : '0');
}
printf("\033[%cm-----------@\n\033[0m阳之镐*%d\n\033[7m阴之镐*%d\033[0m\n", iyy % 2 ? '7' : '0', iyi, iya);
}
int main() {
enum WASD wp = W;
int i = 0;
int ia = 0;
int iyi = 0;
int iya = 0;
int iyy = 0;
YYS yys[10] = { {YI,0,1}, {YI,1,7}, {YA,0,7}, {YA,0,8}, {YA,2,0}, {YA,7,5}, {SW,0,3}, {SW,0,9}, {SW,6,3}, {SW,7,7} };
char ch = 0;
char strmaze[11][11] = {
'P','-','*','&',' ',' ','*','+','+','&',' ',
'*','*','*',' ','*',' ','*','-','*','*',' ',
'+',' ',' ',' ',' ','*','*','*','*',' ',' ',
'*','*','*','*','*',' ',' ',' ','*',' ',' ',
'*',' ',' ',' ','*','*','*',' ','*','*','*',
'*','*','*',' ',' ',' ',' ','*','*',' ',' ',
'*',' ','*','&','*',' ',' ',' ','*',' ',' ',
'*','*',' ','*','*','+','*','&',' ',' ',' ',
'*','*',' ','*',' ',' ',' ',' ',' ','*','*',
'*',' ',' ',' ',' ',' ',' ',' ','*','*','*',
' ','*','*','*',' ',' ','*','*','*','*','G'
};
int yiya[11][11] = { 0 };
for (i = 0; i < 121; i++) {
switch (strmaze[0][i]) {
case '*':
yiya[0][i] = 1;
break;
case ' ':
yiya[0][i] = 0;
break;
default:
i && (yiya[0][i] = 2), i || (yiya[0][i] = 0);
break;
}
}
char strmazer[11][11] = { 0 };
int yiyar[11][11] = { 0 };
memcpy(strmazer, strmaze, sizeof strmaze);
memcpy(yiyar, yiya, sizeof yiya);
char* cp = &strmaze[0][0];
printf("\033[0m欢迎你来玩\033[4;7m阴\033[0m\033[4m阳\033[0m迷宫,在这个迷宫中,“P”是你,空格是你可以走的地方,“\033[32;1mG\033[0m”为\033[32;1m终\033[7m点\033[0m,输入“q”来用掉一把阳之镐破墙,\033[7m输入“e”来用掉一把阴之镐造墙\033[0m,输入“r”即可重置迷宫,在“&”上输入“z”就可以把“*”切换成\033[7m空格\033[0m,空格切换成“\033[7m*\033[0m”,再输入一次即可变回原样,而你只要走到\033[32;1m终\033[7m点\033[0m,就可以\033[32;1m赢\033[0m了,你听懂了吗?");
Sleep(7500);
system("cls");
while ('G' == strmaze[10][10]) {
int ix = (cp - &strmaze[0][0]) / 11;
int iy = (cp - &strmaze[0][0]) % 11;
for (i = 0; i < 6; i++) {
' ' == strmaze[yys[i].ix][yys[i].iy] && (strmaze[yys[i].ix][yys[i].iy] = '%');
}
for (; i < 10; i++) {
' ' == strmaze[yys[i].ix][yys[i].iy] && (strmaze[yys[i].ix][yys[i].iy] = '&');
}
printmaze(strmaze, iyi, iya, iyy);
scanf("%c", &ch);
while ('\n' != getchar()) {
;
}
*cp = ' ';
switch (ch) {
case 'w':
for (i = 0; i < 11; i++) {
if (cp == &strmaze[0][i]) {
break;
}
}
11 == i && '*' != *(cp - 11) && (cp -= 11);
wp = W;
break;
case 'a':
for (i = 0; i < 11; i++) {
if (cp == &strmaze[i][0]) {
break;
}
}
11 == i && '*' != *(cp - 1) && cp--;
wp = A;
break;
case 's':
for (i = 0; i < 11; i++) {
if (cp == &strmaze[10][i]) {
break;
}
}
11 == i && '*' != *(cp + 11) && (cp += 11);
wp = S;
break;
case 'd':
for (i = 0; i < 11; i++) {
if (cp == &strmaze[i][10]) {
break;
}
}
11 == i && '*' != *(cp + 1) && cp++;
wp = D;
break;
case 'q':
if (iyi) {
switch (wp) {
case W:
ix && '*' == *(cp - 11) && 2 != yiya[ix - 1][iy] && (*(cp - 11) = ' ', yiya[ix - 1][iy] = 0, iyi--);
break;
case A:
iy && '*' == *(cp - 1) && 2 != yiya[ix][iy - 1] && (*(cp - 1) = ' ', yiya[ix][iy - 1] = 0, iyi--);
break;
case S:
10 != ix && '*' == *(cp + 11) && 2 != yiya[ix + 1][iy] && (*(cp + 11) = ' ', yiya[ix + 1][iy] = 0, iyi--);
break;
case D:
10 != iy && '*' == *(cp + 1) && 2 != yiya[ix][iy + 1] && (*(cp + 1) = ' ', yiya[ix][iy + 1] = 0, iyi--);
break;
default:
break;
}
}
break;
case 'e':
if (iya) {
switch (wp) {
case W:
ix && ' ' == *(cp - 11) && 2 != yiya[ix - 1][iy] && (*(cp - 11) = '*', yiya[ix - 1][iy] = 1, iya--);
break;
case A:
iy && ' ' == *(cp - 1) && 2 != yiya[ix][iy - 1] && (*(cp - 1) = '*', yiya[ix][iy - 1] = 1, iya--);
break;
case S:
10 != ix && ' ' == *(cp + 11) && 2 != yiya[ix + 1][iy] && (*(cp + 11) = '*', yiya[ix + 1][iy] = 1, iya--);
break;
case D:
10 != iy && ' ' == *(cp + 1) && 2 != yiya[ix][iy + 1] && (*(cp + 1) = '*', yiya[ix][iy + 1] = 1, iya--);
break;
default:
break;
}
}
break;
case 'z':
for (i = 6; i < 10; i++) {
if (cp == &strmaze[yys[i].ix][yys[i].iy]) {
iyy++;
for (ia = 0; ia < 121; ia++) {
if (2 != yiya[0][ia]) {
if (yiya[0][ia]) {
strmaze[0][ia] = ' ';
yiya[0][ia] = 0;
}
else {
strmaze[0][ia] = '*';
yiya[0][ia] = 1;
}
}
}
}
}
break;
case 'r':
iyy = 0;
iyi = 0;
iya = 0;
cp = &strmaze[0][0];
memcpy(strmaze, strmazer, sizeof strmaze);
memcpy(yiya, yiyar, sizeof yiya);
wp = W;
for (i = 0; i < 2; i++) {
yys[i].yy = YI;
}
for (; i < 10; i++) {
i < 6 && (yys[i].yy = YA), i < 6 || (yys[i].yy = SW);
}
break;
default:
break;
}
*cp = 'P';
system("cls");
for (i = 0; i < 6; i++) {
if (cp == &strmaze[yys[i].ix][yys[i].iy] && N != yys[i].yy) {
i < 2 && iyi++, i < 2 || iya++;
yys[i].yy = N;
}
}
}
system("color 0A");
printf("恭喜你\033[37m,\033[32;1;7m你赢了\033[32;1m\n");
return 0;
}
程序的流程图
程序游玩的效果
阴阳迷宫
下一篇博客要说的东西
C语言推箱子迷宫