Problem: 82. 删除排序链表中的重复元素 II

👨‍🏫 灵神题解

Code

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode() {}
 *     ListNode(int val) { this.val = val; }
 *     ListNode(int val, ListNode next) { this.val = val; this.next = next; }
 * }
 */
class Solution {
    public ListNode deleteDuplicates(ListNode head) {
        ListNode dummy = new ListNode(0, head);
        ListNode cur = dummy;
        while(cur.next != null && cur.next.next != null){
            int val = cur.next.val;//这里是下一个节点的值
            if(cur.next.next.val == val)//重复的情况
            {
                while(cur.next != null && cur.next.val == val){
                    cur.next = cur.next.next; //删除与重复值相等的所有节点
                }
            }else{ // 不重复则跳过继续处理下一个
                cur = cur.next;
            }
        }
        return dummy.next;
    }
}