题目：
1、求一元二次方程ax2+bx+c=0的实根。如果方程没有实根，则利用异常处理处理机制输出有关警告信息
2、学校的人事部门保留了有关学生的部分数据（学号、姓名、年龄、住址）。教务部门也保留了学生的另一些数据（学号、姓名、性别，成绩），两个部门分别编写了本部门的学生数据管理程序，其中都用了Student作为类名。现在要求在全校的学生数据管理程序中调用这两个部门的学生数据，分别输出两种内容的学生数据，要求用C++编程，使用命名空间。
参考代码：
1、
#include <iostream>
#include <cmath>
using namespace std;
double q(double,double,double);
void main(){
double a,b,c,p,x1,x2;
cout<<"请输入abc:";
cin>>a>>b>>c;
p=-b/(2*a);
try{
x1=p+q(a,b,c);
x2=p-q(a,b,c);
cout<<"x1="<<x1<<endl<<"x2="<<x2<<endl;
}
catch(double d){
cout<<"a="<<a<<",b="<<b<<",c="<<c<<",disc="<<d<<",error!"<<endl;}
cout<<"end"<<endl;
}
double q(double a,double b,double c)
{double t;
t=b*b-4*a*c;
if (t<0) throw t;
return sqrt(t)/(2*a);
}
2、
#include <string>//H1.h
namespace student1
{
class Student
{
public:
Student(int n, string nam, int a, string addr)
{
num = n; name = nam; age = a; address = addr;
}
void show_data();
private:
int num;
string name;
int age;
string address;
};
void Student::show_data()
{
cout << "num:" << num << " name:" << name << " age:" << age
<< " address:" << address << endl;
}
}
#include <string>//H2.h
namespace student2
{
class Student
{
public:
Student(int n, string nam, char s, float sco)
{
num = n; name = nam; sex = s; score = sco;
}
void show_data();
private:
int num;
string name;
char sex;
float score;
};
void Student::show_data()
{
cout << "num:" << num << " name:" << name << " sex:" << sex
<< " score:" << score << endl;
}
}
#include <iostream>//Main.cpp
using namespace std;
#include "H1.h"
#include "H2.h"
using namespace std;
using namespace student1;
void main()
{
Student stud1(1001, "zhang", 23, "Beijing,Siheyuan");
stud1.show_data();
student2::Student stud2(1102, "Li", 'f', 89.5);
stud2.show_data();
}
