1. 词频统计

题目描述

样例输入

代码

#include <bits/stdc++.h>

using namespace std;

int main()
{
    int n,m;cin>>n>>m;
    vector<int> ans1(m,0),ans2(m,0);
    while (n --) {
        int t;cin>>t;
        vector<int> vis(m+1,0);
        for (int i = 1;i <= t;i ++) {
            int x;cin>>x;
            vis[x] ++;
        }
        for (int i = 0;i < m;i ++) {
            if (vis[i+1]) {
                ans1[i] ++;
            }
            ans2[i] += vis[i+1];
        }
    }
    for (int i = 0;i < m;i ++) {
        cout<<ans1[i]<<" "<<ans2[i]<<endl;
    }
}

2. 相似度计算

题目描述

样例输入

代码

#include <bits/stdc++.h>

using namespace std;

int main()
{
    int n,m;
    cin>>n>>m;
    vector<string> s1(n),s2(m);
    string s;
    set<string> ans2;map<string,int> ans1;
    for (int i = 0;i < n;i ++) {
        cin>>s;
        for (int j = 0;j < s.size();j ++) {
            if (s[j] >= 'A'&&s[j] <= 'Z') {
                s[j] = s[j] - 'A' + 'a';
            }
        }
        s1[i] = s;
        ans2.insert(s);
        //cout<<s<<endl;
        if (ans1.find(s1[i])==ans1.end())
        ans1[s1[i]] = 1;
        // cout<<s1[i]<<endl;
    }
    int answer1 = 0;
    for (int i = 0;i < m;i ++) {
        cin>>s;
        for (int j = 0;j < s.size();j ++) {
            if (s[j] >= 'A'&& s[j] <= 'Z') {
                s[j] = s[j] - 'A' + 'a';
            }
        }
        s2[i] = s;
        //cout<<s<<endl;
        ans2.insert(s);
        if (ans1.find(s2[i])!=ans1.end()) {
            answer1++;
            //cout<<ans1.size()<<endl;
            ans1.erase(s2[i]);
            //cout<<ans1.size()<<endl;
        }
    }
    cout<<answer1<<endl<<ans2.size()<<endl;
}

3. 化学方程式配平

题目描述

样例输入

代码

#include <bits/stdc++.h>

using namespace std;
double a[105][105];
const double eps = 1e-8;
int huajian2(int n,int m)//亦或矩阵的化简  
{
    int row = 1;
	for (int i = 1;i <= m;i ++) {
        bool flag = 0;
        for (int j = row;j <= n;j ++) {
            if (fabs(a[j][i]) > eps) flag = 1;
        } 
        if (!flag) continue;
        if (fabs(a[row][i])<eps) {
            for (int j = row + 1;j <= n;j ++) {
                if (a[j][i]) {
                    for (int k = i;k <= m;k ++) 
                        swap(a[row][k],a[j][k]);
                    break;
                }
            }
        }
        
        for (int j = row+1;j <= n;j ++) {
            for (int k = i+1;k <= m;k ++) {
                a[j][k] -= a[row][k]*(a[j][i]/a[row][i]);
            }
            a[j][i] = 0;
        }   
        row ++;
    }
    int cnt = 0;
    for (int i = 1;i <= n;i ++) {
        bool flag = 0;
        for (int j = 1;j <= m; j++ )
            if (fabs(a[i][j])>eps) flag = 1;
        if (flag) cnt ++;
    }
    return cnt;
}
double to_int(string s) 
{
    double x = 0;
    for (int i = 0;i < s.size();i ++) {
        x=x*10+s[i]-'0';
    }
    return x*1.0;
}
void solve()
{
    int t;cin>>t;
    int c_cnt  = 0; 
    map<string,int> s_sum;
    for (int i = 1;i <=100;i ++ ) {
        for (int j = 1;j <= 100;j ++) a[i][j] = 0*1.0;
    }
    for (int i = 1;i <= t;i ++) {
        string s;cin>>s;
        string t_s = "",int_s = "";

        vector<double> i1;vector<string> s1;
        for (int j = 0;j < s.size();j ++)
        {
            if (s[j] >= 'a' && s[j] <= 'z') {
                t_s += s[j];
            } else {
                if (t_s!="")
                    s1.push_back(t_s);
                if (s_sum.find(t_s) == s_sum.end()) 
                    s_sum[t_s] = ++ c_cnt;
                t_s = "";
            } 
        }
        int_s = "";
        for (int j = 0;j < s.size();j ++) {
            if (isdigit(s[j])) {
                int_s += s[j];
            } else {
                if (int_s!="")
                    i1.push_back(to_int(int_s));
                int_s = "";
            }
        }
        i1.push_back(to_int(int_s));
        int_s = "";
        
        for (int j = 0;j < s1.size();j ++) {
            a[s_sum[s1[j]]][i] = i1[j];
        }
    }
    
    int ans = huajian2(c_cnt,t);
    if (ans < t) cout<<"Y"<<endl;
    else cout<<"N"<<endl;
}

int main()
{
    // if (eps>0)
    // cout<<eps<<endl;
    int n;cin>>n;
    while (n --) {
        solve();
    }
}

4. 十滴水

题目描述

输入格式及样例输入

代码

#include <bits/stdc++.h>

using namespace std;

int main() 
{
    int c,m,n;
    cin>>c>>m>>n;
    map<int,int> water;
    set<int> w_arr;
    for (int i = 1;i <= m;i ++) {
        int x,w;cin>>x>>w;
        w_arr.insert(x);
        water[x] = w;
    }
    set<int> five_s;
    while (n --) {
        int p;cin>>p;
        water[p] ++;
        
        if (water[p] >= 5) {
            five_s.insert(p);
        }
        // for (auto x:five_s) {
        //     cout<<x<<" :  ";
        // }cout<<endl;
        // for (auto x:w_arr) {
        //     cout<<x<<" ::  ";
        // }cout<<endl;
        while (int(five_s.size())!=0) {
            int xx = *(five_s).begin();
            set<int>::iterator iter = w_arr.find(xx);
            if(w_arr.size() == 1) {
                w_arr.erase(xx);break;
            }
            iter++;
            if ( iter != w_arr.end()) {
                // iter++;
                int xx = *(iter);
                water[xx] ++;
                if (water[xx] >= 5)  {
                    five_s.insert(xx);
                    // vis[xx] = 1;
                } 
            }
            iter  = w_arr.find(xx);
            
            if (iter != w_arr.begin()){
                iter--;
                int xx = *iter;
                water[xx] ++;
                // cout<<xx<<":"<<i<<endl;
                if (water[xx] >= 5)  {
                    five_s.insert(xx);
                    // vis[xx] = 1;
                } 
            }
            five_s.erase(five_s.find(xx));
            w_arr.erase(w_arr.find(xx));
            water.erase(water.find(xx));
        }
        // for (auto x:w_arr) {
        //     cout<<x<<" :  "<<water[x]<<"!!!";
        // }cout<<endl;
        cout<<w_arr.size()<<endl;
    }
}