基本使用

信号量，用来限制能同时访问共享资源的线程上限。

 public static void main(String[] args) {
        // 1. 创建 semaphore 对象
        Semaphore semaphore = new Semaphore(3);
        // 2. 10个线程同时运行
        for (int i = 0; i < 10; i++) {
            new Thread(() -> {
                // 3. 获取许可
                try {
                    semaphore.acquire();
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
                try {
                    log.debug("running...");
                    sleep(1);
                    log.debug("end...");
                } finally {
                    // 4. 释放许可
                    semaphore.release();
                }
            }).start();
        }
    }

输出

07:35:15.485 c.TestSemaphore [Thread-2] - running... 
07:35:15.485 c.TestSemaphore [Thread-1] - running... 
07:35:15.485 c.TestSemaphore [Thread-0] - running... 
07:35:16.490 c.TestSemaphore [Thread-2] - end... 
07:35:16.490 c.TestSemaphore [Thread-0] - end... 
07:35:16.490 c.TestSemaphore [Thread-1] - end... 
07:35:16.490 c.TestSemaphore [Thread-3] - running... 
07:35:16.490 c.TestSemaphore [Thread-5] - running... 
07:35:16.490 c.TestSemaphore [Thread-4] - running... 
07:35:17.490 c.TestSemaphore [Thread-5] - end... 
07:35:17.490 c.TestSemaphore [Thread-4] - end... 
07:35:17.490 c.TestSemaphore [Thread-3] - end... 
07:35:17.490 c.TestSemaphore [Thread-6] - running... 
07:35:17.490 c.TestSemaphore [Thread-7] - running... 
07:35:17.490 c.TestSemaphore [Thread-9] - running... 
07:35:18.491 c.TestSemaphore [Thread-6] - end... 
07:35:18.491 c.TestSemaphore [Thread-7] - end... 
07:35:18.491 c.TestSemaphore [Thread-9] - end... 
07:35:18.491 c.TestSemaphore [Thread-8] - running... 
07:35:19.492 c.TestSemaphore [Thread-8] - end... 

Semaphore 应用-改进数据库连接池

semaphore 实现

• 使用 Semaphore 限流，在访问高峰期时，让请求线程阻塞，高峰期过去再释放许可，当然它只适合限制单机线程数量，并且仅是限制线程数，而不是限制资源数（例如连接数，请对比 Tomcat LimitLatch 的实现）
• 用 Semaphore 实现简单连接池，对比『享元模式』下的实现（用wait notify），性能和可读性显然更好，注意下面的实现中线程数和数据库连接数是相等的

@Slf4j(topic = "c.Pool")
class Pool {
    // 1. 连接池大小
    private final int poolSize;

    // 2. 连接对象数组
    private Connection[] connections;

    // 3. 连接状态数组 0 表示空闲， 1 表示繁忙
    private AtomicIntegerArray states;

    private Semaphore semaphore;

    // 4. 构造方法初始化
    public Pool(int poolSize) {
        this.poolSize = poolSize;
        // 让许可数与资源数一致
        this.semaphore = new Semaphore(poolSize);
        this.connections = new Connection[poolSize];
        this.states = new AtomicIntegerArray(new int[poolSize]);
        for (int i = 0; i < poolSize; i++) {
            connections[i] = new MockConnection("连接" + (i+1));
        }
    }

    // 5. 借连接
    public Connection borrow() {// t1, t2, t3
        // 获取许可
        try {
            semaphore.acquire(); // 没有许可的线程，在此等待
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        for (int i = 0; i < poolSize; i++) {
            // 获取空闲连接
            if(states.get(i) == 0) {
                if (states.compareAndSet(i, 0, 1)) {
                    log.debug("borrow {}", connections[i]);
                    return connections[i];
                }
            }
        }
        // 不会执行到这里
        return null;
    }
    // 6. 归还连接
    public void free(Connection conn) {
        for (int i = 0; i < poolSize; i++) {
            if (connections[i] == conn) {
                states.set(i, 0);
                log.debug("free {}", conn);
                semaphore.release();
                break;
            }
        }
    }
}

Semaphore 原理

1. 加锁解锁流程

Semaphore 有点像一个停车场，permits 就好像停车位数量，当线程获得了 permits 就像是获得了停车位，然后
停车场显示空余车位减一

刚开始，permits（state）为 3，这时 5 个线程来获取资源

假设其中 Thread-1，Thread-2，Thread-4 cas 竞争成功，而 Thread-0 和 Thread-3 竞争失败，进入 AQS 队列park 阻塞

这时 Thread-4 释放了 permits，状态如下

接下来 Thread-0 竞争成功，permits 再次设置为 0，设置自己为 head 节点，断开原来的 head 节点，unpark 接下来的 Thread-3 节点，但由于 permits 是 0，因此 Thread-3 在尝试不成功后再次进入 park 状态

2. 源码分析

static final class NonfairSync extends Sync {
    private static final long serialVersionUID = -2694183684443567898L;
    NonfairSync(int permits) {
        // permits 即 state
        super(permits);
    }

    // Semaphore 方法, 方便阅读, 放在此处
    public void acquire() throws InterruptedException {
        sync.acquireSharedInterruptibly(1);
    }
    // AQS 继承过来的方法, 方便阅读, 放在此处
    public final void acquireSharedInterruptibly(int arg)
            throws InterruptedException {
        if (Thread.interrupted())
            throw new InterruptedException();
        if (tryAcquireShared(arg) < 0)
            doAcquireSharedInterruptibly(arg);
    }

    // 尝试获得共享锁
    protected int tryAcquireShared(int acquires) {
        return nonfairTryAcquireShared(acquires);
    }

    // Sync 继承过来的方法, 方便阅读, 放在此处
    final int nonfairTryAcquireShared(int acquires) {
        for (;;) {
            int available = getState();
            int remaining = available - acquires;
            if (
                // 如果许可已经用完, 返回负数, 表示获取失败, 进入 doAcquireSharedInterruptibly
                    remaining < 0 ||
                            // 如果 cas 重试成功, 返回正数, 表示获取成功
                            compareAndSetState(available, remaining)
            ) {
                return remaining;
            }
        }
    }

    // AQS 继承过来的方法, 方便阅读, 放在此处
    private void doAcquireSharedInterruptibly(int arg) throws InterruptedException {
        final Node node = addWaiter(Node.SHARED);
        boolean failed = true;
        try {
            for (;;) {
                final Node p = node.predecessor();
                if (p == head) {
                    // 再次尝试获取许可
                    int r = tryAcquireShared(arg);
                    if (r >= 0) {
                        // 成功后本线程出队（AQS）, 所在 Node设置为 head
                        // 如果 head.waitStatus == Node.SIGNAL ==> 0 成功, 下一个节点 unpark
                        // 如果 head.waitStatus == 0 ==> Node.PROPAGATE
// r 表示可用资源数, 为 0 则不会继续传播
                        setHeadAndPropagate(node, r);
                        p.next = null; // help GC
                        failed = false;
                        return;
                    }
                }
                // 不成功, 设置上一个节点 waitStatus = Node.SIGNAL, 下轮进入 park 阻塞
                if (shouldParkAfterFailedAcquire(p, node) &&
                        parkAndCheckInterrupt())
                    throw new InterruptedException();
            }
        } finally {
            if (failed)
                cancelAcquire(node);
        }
    }

    // Semaphore 方法, 方便阅读, 放在此处
    public void release() {
        sync.releaseShared(1);
    }

    // AQS 继承过来的方法, 方便阅读, 放在此处
    public final boolean releaseShared(int arg) {
        if (tryReleaseShared(arg)) {
            doReleaseShared();
            return true;
        }
        return false;
    }

// Sync 继承过来的方法, 方便阅读, 放在此处
protected final boolean tryReleaseShared(int releases) {
    for (;;) {
        int current = getState();
        int next = current + releases;
        if (next < current) // overflow
            throw new Error("Maximum permit count exceeded");
        if (compareAndSetState(current, next))
            return true;
    }
}
}