2023每日刷题（六十九）

Leetcode—86.分隔链表

实现代码

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     struct ListNode *next;
 * };
 */
struct ListNode* partition(struct ListNode* head, int x) {
    struct ListNode* small = (struct ListNode*)malloc(sizeof(struct ListNode));
    struct ListNode* big = (struct ListNode*)malloc(sizeof(struct ListNode));
    small->next = NULL;
    big->next = NULL;
    struct ListNode* r1 = small;
    struct ListNode* r2 = big;
    while(head != NULL) {
        if(head->val < x) {
            r1->next = head;
            r1 = head;
        } else {
            r2->next = head;
            r2 = head;
        }
        head = head->next;
    }
    r2->next = NULL;
    r1->next = big->next;
    return small->next;
}

运行结果

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