100131. 使三个字符串相等
⭐ AC code
class Solution {
public int findMinimumOperations(String s1, String s2, String s3) {
int len1 = s1.length();
int len2 = s2.length();
int len3 = s3.length();
int n = Math.min(len1,len2);
n = Math.min(n,len3);
int i = 0;
while(i < n)
{
if(s1.charAt(i) != s2.charAt(i) || s2.charAt(i) != s3.charAt(i))
break;
i++;
}
if(i == 0)
return -1;
return len1 + len2 + len3 - i * 3;
}
}
100122. 区分黑球与白球
求 0 左边 1 的个数(交换两个 0 是没有意义的)
⭐ AC code
class Solution {
public long minimumSteps(String s) {
long ans = 0;
long cnt = 0;
for(int i = 0; i < s.length(); i++)
{
char c = s.charAt(i);
if(c == '0')
ans += cnt;
else
cnt++;
}
return ans;
}
}
100119. 最大异或乘积
⭐ AC code
import java.math.BigDecimal;
class Solution {
public int maximumXorProduct(long a, long b, int n) {
int mod = (int) (1e9 + 7);
BigDecimal pre = BigDecimal.valueOf(a).multiply(BigDecimal.valueOf(b));
for (int i = n - 1; i >= 0; i--) {
long a1 = a ^ (1L << i);
long b1 = b ^ (1L << i);
BigDecimal cur = BigDecimal.valueOf(a1).multiply(BigDecimal.valueOf(b1));
if (cur.subtract(pre).doubleValue() > 0) {
a = a1;
b = b1;
pre = cur;
}
}
long a1 = (a) % mod;
long b1 = (b) % mod;
return (int) (a1 * b1 % mod);
}
}
👨🏫 大佬题解