跑步锻炼 - 蓝桥云课 (lanqiao.cn)

题目描述

题目分析 

简单枚举，对于+2的情况特判即可

#include<bits/stdc++.h>
using namespace std;
int num, ans, flag;
int m[13] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; 
bool is_ren(int n)
{
	if((n % 4 == 0 && n % 100 != 0) || n % 400 == 0)return true;
	return false;
}
int main()
{
	for(int i = 2000; i <= 2020; i ++)
	{
		if(is_ren(i))m[2] = 29;
		else m[2] = 28;
		for(int j = 1; j <= 12; j ++)
		{
			for(int k = 1; k <= m[j]; k ++)
			{
				num ++;
				if(k == 1 || (num % 7 - 3) == 0)ans += 2;
				else ans += 1; 
				if(i == 2020 && j == 10 && k == 1)
				{
					flag = 1;
					break;
				}
			}
			if(flag)break;
		}
		if(flag)break;
	}
	cout << ans;
	return 0;
}