力扣sql中等篇练习(二十九)

1 计算每个销售人员的影响力

1.1 题目内容

1.1.1 基本题目信息1

1.1.2 基本题目信息2

1.1.3 示例输入输出

a 示例输入

b 示例输出

1.2 示例sql语句

# Write your MySQL query statement below
SELECT s1.salesperson_id,s1.name,IFNULL(t.total,0) total
FROM Salesperson s1
LEFT JOIN
(
    SELECT c.salesperson_id,SUM(s.price) total
    FROM Sales s 
    INNER JOIN Customer c 
    ON s.customer_id=c.customer_id
    GROUP BY c.salesperson_id
)t
ON s1.salesperson_id=t.salesperson_id

1.3 运行截图

2 将表中的空值更改为前一个值

2.1 题目内容

2.1.1 基本题目信息

2.1.2 示例输入输出

2.2 示例sql语句

# row_number() 显示具体行数
WITH T as
(
    SELECT *,row_number() over() rk
    FROM CoffeeShop
),
P as
(
  SELECT t2.id,t2.rk b_rk,t1.rk a_rk,(SELECT drink FROM T t3 WHERE t3.rk=MAX(t1.rk)) drink
  FROM T t1
  INNER JOIN T t2
  ON t2.drink is null AND t1.rk<t2.rk AND t1.drink IS NOT NULL
  GROUP BY t2.id
)
SELECT t4.id,IFNULL(t4.drink,(SELECT p1.drink FROM P p1 WHERE p1.id=t4.id AND p1.b_rk=t4.rk)) drink
FROM T t4

2.3 运行截图

3 开除员工

3.1 题目内容

3.1.1 基本题目信息1

3.1.2 基本题目信息2

3.1.3 示例输入输出

a 示例输入

b 示例输出

3.2 示例sql语句

# 找到没有被开除的,然后去子查询筛选掉,剩下的就是开除的了
# 注意:分钟数是向上取整的,先求秒针数,然后除以60,使用ceiling函数向上取整就行
SELECT employee_id
FROM Employees
WHERE employee_id NOT IN
(
    SELECT e.employee_id
    FROM Employees e
    INNER JOIN
    (
        SELECT employee_id,SUM(CEILING(TimeStampDiff(SECOND,in_time,out_time)/60)/60) total
        FROM Logs
        GROUP BY employee_id
    )t
    ON e.employee_id=t.employee_id AND t.total>=e.needed_hours
)

3.3 运行截图