1、通过试验（即编写带有此类问题的程序）观察系统如何处理整数上道、浮占数上溢和浮点数下溢的

int main(int argc, char** argv)
{
    int intMax = 2147483647;
    float floatMax = 3.402823466e+38f;
    float floatMin = -3.402823466e+38f;
    printf("intMax:%d, floatMax:%f, floatMin:%f\n", intMax, floatMax, floatMin);
    printf("intMax + 1:%d, floatMax * 10:%f, floatMin / 10:%f\n", intMax + 1, floatMax * 10, floatMin / 10);
    return 0;
}

2.编写一个程序，要求提示输入一个ASCII码值（如，66），然后打印输入的字符。

int main(int argc, char** argv)
{
    int ascii;
    printf("Enter an ASCII code: ");
    scanf_s("%d", &ascii);
    printf("%d is the ASCII code for %c.\n", ascii, ascii);
    return 0;
}

3.编写一个程序，发出一声警报，然后打印下面的文本：
Startled by the sudden sound, Sally shouted
"By the Great Pumpkin, what was that!"

int main(int argc, char** argv)
{
    printf("%c", '\a');
    printf("Startled by the sudden sound, Sally shouted\n\"By the Great Pumpkin, what was that!\"");
    return 0;
}

4、编写一个程序，读取一个浮点数，先打印成小数占形式。再打印成指数形式。然后，如果系统支持，再打印成p记数法（即十六进制记数法），按以下格式输出（实际显示的指数位数因系统而异）：
Enter a floating-point value: 64.25
fixed-point notation; 64.250000
exponential notation: 6.425000e+01
p notation: 0x1.01p+6

int main(int argc, char** argv)
{
    float num;
    printf("Enter a floating-point value: ");
    scanf_s("%f", &num);
    printf("fixed-point notation: %f\n", num);
    printf("exponential notation: %e\n", num);
    printf("p notation: %a\n", num);
    return 0;
}

5.一年大约有3.156×10'秒。编写一个程序，提示用户输入年龄，然后显示该年龄对应的秒数。

int main(int argc, char** argv)
{
    int age;
    printf("Enter your age:");
    scanf_s("%d", &age);
    printf("You are %e seconds old\n", age * 3.156e7);
    return 0;
}

6. 1个水分子的质量约为3.0×10-3克。1夸脱水大约是950克。编写一个程序，提示用户输入水的夸
脱数，并显示水分子的数量。

int main(int argc, char** argv)
{
    float mass_mol = 3.0e-23;    /* mass of water molecule in grams */
    float mass_qt = 950;        /* mass of quart of water in grams */
    float quarts;
    float molecules;
    printf("Enter the number of quarts of water: ");
    scanf_s("%f", &quarts);
    molecules = quarts * mass_qt / mass_mol;
    printf("%f quarts of water contain %e molecules.\n", quarts, molecules);
    return 0;
}

7.1英寸相当于2.54厘米。编写一个程序，提示用户输入身高(/英寸)，然后以厘米为单位显示身高。

int main(int argc, char** argv)
{
    int height;
    printf("Enter your height(inch):");
    scanf_s("%d", &height);
    printf("You are %.2f cm height\n", height * 2.54);
    return 0;
}

8.在美国的体积测量系统中，1品脱等于2杯，1杯等于8盎司，1盎司等于2大汤勺，1大汤勺等于
3茶勺。编写一个程序，提示用户输入杯数，并以品脱、盎司、汤勺、茶勺为单位显示等价容量。

int main(int argc, char** argv)
{
    int cups;
    printf("Enter the cups:");
    scanf_s("%d", &cups);
    float pint = cups * 0.5;
    float ounce = cups * 8;
    float spoons = ounce * 2;
    float tea_spoons = spoons * 3;
    printf("%d cups equals %.2f pint, %.2f ounce, %.2f spoons, %.2f tea_spoons\n", cups, pint, ounce, spoons, tea_spoons);
    return 0;
}