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问题:

解答:

#include <iostream>
#include <fstream>
using namespace std;

int main(int argc,char*argv[])
{
	if (argc < 3)
	{
		cout << "Usage: " << argv[0] << " srcfile desfile" << endl;
		exit(EXIT_FAILURE);
	}
	char ch;
	ifstream fin(argv[1], ios_base::in);
	ofstream fout(argv[2], ios_base::out);
	if (!fin.is_open())
	{
		cout << "Can't open the file:" << argv[1] << "!" << endl;
		exit(EXIT_FAILURE);
	}
	if (!fout.is_open())
	{
		cout << "Can't open the file:" << argv[2] << "!" << endl;
		exit(EXIT_FAILURE);
	}
	while (fin.get(ch))
	{
		fout << ch;
	}
	fin.close();
	fout.close();

	return 0;
}

运行结果:

注意:

• 要先在vs中编译一下,再进行g++ main.cpp -o file.exe
• 这里的argc的参数个数就是三哦.

2024年9月22日15:21:20