time limit per test

1 second

memory limit per test

256 megabytes

You are given two integers aa and bb (a≤ba≤b). Over all possible integer values of cc (a≤c≤ba≤c≤b), find the minimum value of (c−a)+(b−c)(c−a)+(b−c).

Input

The first line contains tt (1≤t≤551≤t≤55) — the number of test cases.

Each test case contains two integers aa and bb (1≤a≤b≤101≤a≤b≤10).

Output

For each test case, output the minimum possible value of (c−a)+(b−c)(c−a)+(b−c) on a new line.

Example

Input

Copy

3

1 2

3 10

5 5

Output

Copy

1
7
0

Note

In the first test case, you can choose c=1c=1 and obtain an answer of (1−1)+(2−1)=1(1−1)+(2−1)=1. It can be shown this is the minimum value possible.

In the second test case, you can choose c=6c=6 and obtain an answer of (6−3)+(10−6)=7(6−3)+(10−6)=7. It can be shown this is the minimum value possible.

解题说明:：水题，结果就是b-a

#include <stdio.h>

int main() 
{
	int t;
	scanf("%d", &t);
	while (t--)
	{
		int a, b;
		scanf("%d%d", &a, &b);
		printf("%d\n", b - a);
	}
	return 0;
}