python实现井字棋游戏
游戏规则，有三个井字棋盘，看谁连成的直线棋盘多谁就获胜
棋盘的展现形式为 棋盘号ABC和位置数字1-9
输入A1 代表在A棋盘1号位数下棋 

效果图如下

部分源码如下：

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boardLists=[[0,1,2,3,4,5,6,7,8],[0,1,2,3,4,5,6,7,8], [0,1,2,3,4,5,6,7,8]]
match=[[0,3,6], [1,4,7], [2,5,8], [0, 4, 8]]
boards=[0,1,2]
def showLayout(boards, boardLists):
    begin=0
    end=2
    for i in range(len(boards)):
        if boards[i] == 0:
            print("A     ", end=" ")
        if boards[i] == 1:
            print("B     ", end=" ")
        if boards[i] == 2:
            print("C",end='')
    print("")
    for i in range(len(boards)):
        for j in range(len(boards)):
            if boards[j] == -1:
                continue
            Board0=boardLists[j]
            beginTemp=begin;
            while begin <= end :
                print(Board0[begin], end=" ")
                begin += 1
            begin=beginTemp
            print(" ",end='')
        begin=end+1
        end=end+3
        print("")
showLayout(boards, boardLists)