R4-字符串

动态规划

class Solution:
    def findSubstringInWraproundString(self, s: str) -> int:
        dp=[0]*26
        num=1
        #dp初始化
        dp[ord(s[0])-ord('a')]=1
        for c1,c2 in pairwise(s):
            if not (ord(c2)-ord(c1)-1)%26:
                num+=1
            else:
                num=1
            dp[id]=max(dp[id := ord(c2)-ord('a')],num)
        return sum(dp)

ps:

ord()计算ASCII值

#连取两个
 for c1, c2 in pairwise(p):