1. 题目

2. 分析

3. 代码

class Solution:
    def removeDuplicates(self, nums: List[int]) -> int:
        if len(nums) < 3:
            return len(nums)
        
        i = 0
        j = 1
        k = 2
        while(k < len(nums)):
            if (nums[i] == nums[j]):
                while(k < len(nums) and nums[j] == nums[k] ):
                    k+=1
                if (k < len(nums)):
                    j+=1                
                    i+=1
                    nums[j] = nums[k]
                    k+=1                    
            else:
                j+=1
                i+=1
                nums[j] = nums[k]
                k+=1
        return j+1