solution

测试点4：1 1不符合缘分数定义，但是这个判断能够通过记得排除掉

#include<iostream>
#include<cmath>
using namespace std;
bool judge(int n){
	int t = sqrt(n);
	if(t * t == n) return true;
	return false;
}
int main(){
	int n, m, c, cc, flag = 1;
	scanf("%d%d", &m, &n);
	for(int i = m; i <= n; i++){
		cc = pow(i, 3) - pow(i - 1, 3);
		c = sqrt(cc);
		if(c * c == cc){
			for(int j = 1, k; j <= c; j++){
				k = c - j;
				if(judge(j) && judge(k) && (sqrt(j) - sqrt(k)) == 1){
					if(!(j == 1 && i == 1))printf("%d %d\n", i, (int)sqrt(j));
					flag = 0;
				}
			}
		}
	}
	if(flag) printf("No Solution");
	return 0;
}