题目

思路：

#include <bits/stdc++.h>
using namespace std;
#define int long long
#define pb push_back
#define fi first
#define se second
#define lson p << 1
#define rson p << 1 | 1
const int maxn = 1e6 + 5, inf = 1e18, maxm = 4e4 + 5;
const int N = 1e6;
const int mod = 1e9 + 7;
// const int mod = 998244353;
//const __int128 mod = 212370440130137957LL;
//  int a[1005][1005];
// bool vis[505][505];
int n, m;
int a[maxn];
//int b[maxn];
string s;

// struct Node{
//     int a, b;
//     // int val, id;
//     bool operator<(const Node &u)const{
//         
//     }
// }node[maxn];

//long long ? maxn ? n? m?
void solve(){
    int res = 0;
    int k;
    cin >> n >> k;
    vector<int> b(n + 5, 0);
    for(int i = 1; i <= k; i++){
    	int p, x;
    	cin >> p >> x;
    	b[p] = x;
	}
	for(int i = 1; i <= n; i++){
		if(b[i]){
			for(int j = i - 1; j >= 1; j--){
				if(b[j]) break;
				b[j] = max(1LL, b[j + 1] - 1);
			}
		}
	}
	for(int i = 1; i <= n; i++){//防止没给出 b[n]，因为之前只往左放
		if(!b[i]) b[i] = b[i - 1];//后面全部赋值为最右的给定的b[i], 这样a数组后面这段构造为逆序就可以满足条件
	}
	bool ok = b[1] == 1;
	for(int i = 2; i <= n; i++){
		if(b[i] - b[i - 1] > 1){
			ok = 0;
			break;
		}
	}
	if(!ok){
		cout << -1 << '\n';
		return;
	}
	vector<int> p(n);
	iota(p.begin(), p.end(), 1);//从1开始
//     for(int i = 0; i < n; i++){
//         p[i] = i + 1;
//     }
	sort(p.begin(), p.end(), [&](int i, int j){
		if(b[i] != b[j]) return b[i] < b[j];
		return i > j;
	});
	int cur = 1;
	vector<int> ans(n + 5);
	for(auto x : p){
		ans[x] = cur++;
	}
	for(int i = 1; i <= n; i++){
		cout << ans[i] << " \n"[i == n];
	}
}   
    
signed main(){
    ios::sync_with_stdio(0);
    cin.tie(0);
	 
    int T = 1;
//    cin >> T;
    while (T--)
    {
        solve();
    }
    return 0;
}