SELECT customer_number
FROM Orders
GROUPBY customer_number
havingcount(order_number)=(SELECTmax(o1.number)FROM(SELECTcount(order_number) number
FROM Orders
GROUPBY customer_number
) o1
)
1.3 运行截图
2 游戏玩法分析I
2.1 题目内容
2.1.1 基本题目信息
2.1.2 示例输入输出
2.2 示例sql语句
SELECT player_id,min(event_date) first_login
FROM Activity
GROUPBY player_id;