题目所属分类
辅助栈 或者一个栈
原题链接
设计一个支持 push ,pop ,top 操作,并能在常数时间内检索到最小元素的栈。
实现 MinStack 类:
MinStack() 初始化堆栈对象。
void push(int val) 将元素val推入堆栈。
void pop() 删除堆栈顶部的元素。
int top() 获取堆栈顶部的元素。
int getMin() 获取堆栈中的最小元素。
代码案例:输入:
[“MinStack”,“push”,“push”,“push”,“getMin”,“pop”,“top”,“getMin”]
[[],[-2],[0],[-3],[],[],[],[]]
输出:
[null,null,null,null,-3,null,0,-2]
解释:
MinStack minStack = new MinStack();
minStack.push(-2);
minStack.push(0);
minStack.push(-3);
minStack.getMin(); --> 返回 -3.
minStack.pop();
minStack.top(); --> 返回 0.
minStack.getMin(); --> 返回 -2.
题解
class MinStack {
Stack<Integer> a ;
Stack<Integer> b ;
public MinStack() {
a = new Stack<>();
b = new Stack<>();
b.push(Integer.MAX_VALUE);
}
public void push(int val) {
a.push(val);
b.push(Math.min(val , b.peek()));
}
public void pop() {
a.pop() ;
b.pop();
}
public int top() {
return a.peek();
}
public int getMin() {
return b.peek() ;
}
}
/**
* Your MinStack object will be instantiated and called as such:
* MinStack obj = new MinStack();
* obj.push(val);
* obj.pop();
* int param_3 = obj.top();
* int param_4 = obj.getMin();
*/
class MinStack {
/** initialize your data structure here. */
private Stack<Integer> stack;
private int min;
public MinStack() {
stack = new Stack();
min = Integer.MAX_VALUE;
}
public void push(int x) {
if (x <= min) {
stack.push(min);
min = x;
}
stack.push(x);
}
public void pop() {
if (min == stack.peek()) {
stack.pop();
min = stack.pop();
} else {
stack.pop();
}
if (stack.isEmpty()) {
min = Integer.MAX_VALUE;
}
}
public int top() {
return stack.peek();
}
public int getMin() {
return min;
}
}
/**
* Your MinStack object will be instantiated and called as such:
* MinStack obj = new MinStack();
* obj.push(x);
* obj.pop();
* int param_3 = obj.top();
* int param_4 = obj.getMin();
*/