直接上代码吧

public class TestStream1023 {


    @Test
    public void testPareCom() {
        String res = testPareCom(12, 5, 8);
        System.out.println("逻辑&计算的结果二进制:["+res+"]");
        System.out.println("二级制转十进制数字:"+Integer.valueOf(res,2));
    }

    private String testPareCom(int a, int b, int size) {
        String strA = parseStr(Integer.toBinaryString(a), size);
        String strB = parseStr(Integer.toBinaryString(b), size);
        System.out.println("[" + a + "]的二进制:[" + strA + "]");
        System.out.println("[" + b + "]的二进制:[" + strA + "]");
        char[] charA = strA.toCharArray();
        char[] charB = strB.toCharArray();

        char[] charC = new char[size];
        for (int i = 0; i < size; i++) {
            if (charA[i] == '1' && charB[i] == '1') {
                charC[i] = '1';
            } else {
                charC[i] = '0';
            }
        }
        System.out.println(Arrays.toString(charC));
        return String.valueOf(charC);
    }

    private String parseStr(String strNum, int num) {
        // 0 代表前面补充0
        // 4 代表长度为4
        // d 代表参数为正数型
        //向前补0
        StringBuffer stringBuffer = new StringBuffer();
        stringBuffer.append("%0").append(num).append("d");
        String str = String.format(stringBuffer.toString(), Integer.parseInt(strNum));
        if (str.length() != num) {
            //向后补0
            StringBuffer stringBuffer1 = new StringBuffer(str);
            int jq = num - str.length();
            for (int i = 0; i < jq; i++) {
                stringBuffer1.append("0");
            }
            return stringBuffer1.toString();
        }
        return str;
    }
}

计算结果