SQL编写判断是否为工作日函数编写
最近的自己在写一些功能,遇到了对于工作日的判断,我就看了看sql,来吧!~(最近就是好疲惫)
我们一起看看(针对ORACLE)
1.声明:
CREATE OR REPLACE PACKAGE GZYW_2109_1214.PKG_FUN_GETDAY_HDAY AS
/**
* 通过节假日代码获取指定的日期[查找基准日期前/后N自然/工作日的日期]
* 注：此函数只适用于节假日表中只保存了节假日日期（非工作日记录）的情况 ,
* 警告：若没有设置范围内的节假日信息，此函数会计算出错误的返回日期
* _Stand_Date 基准日期,
* C_MKT_Code 节假日代码,
* N_Interval_Day 间隔天数(大于0向后查找,小于0向前查找,等于0返回基准日期),
* C_Type 日期类型 'W'工作日,'D'自然日,'DW'自然日递延至工作日
*/
Function GETDAY_HDAY(C_HDay_Code varchar2,D_Stand_Date date,N_Interval_Day int,C_Type varchar2) return Date;
END PKG_FUN_GETDAY_HDAY;
2.主体
CREATE OR REPLACE PKG_FUN_GETDAY_HDAY AS
Function getDay_HDay(C_HDay_Code varchar2,
D_Stand_Date date,
N_Interval_Day int,
C_Type varchar2)
return Date as
D_Return Date; /*返回的日期*/
D_Start Date; /*区间开始日期*/
D_End Date; /*区间结束日期*/
D_Tmp Date;
N_Count int := 1;
C_Hday varchar2(20) := C_HDay_Code;
begin
D_Return := D_Stand_Date;
/*判断参数是否合法*/
if (('W' != C_Type) AND ('D' != C_Type) and ('DW' != C_Type)) then
return D_Return;
else
if (('D' = C_Type) or ('DW' = C_Type)) then
D_Return := D_Stand_Date + N_Interval_Day;
else
/*工作日的推算*/
D_Start := D_Stand_Date;
D_End := D_Stand_Date + N_Interval_Day;
D_Return := D_End;
while (true) loop
exit when N_Count = 0;
begin
if (N_Interval_Day >= 1) then
select /*+RESULT_CACHE*/ count(*)
into N_Count
from T_P_BI_HDAY_SUB a
where a.C_HDay_Code = C_Hday
and a.D_HDay > D_Start
and a.D_HDay <= D_End
and a.c_Date_Type = 'H'
and a.N_Check_State = 1;
if (N_Count > 0) then
D_Start := D_End;
D_End := D_End + N_Count;
D_Return := D_End;
else
exit; /*退出*/
end if;
else
/*如果是逆序*/
if (D_Start > D_End) then
D_Tmp := D_End;
D_End := D_Start;
D_Start := D_Tmp;
end if;
select /*+RESULT_CACHE*/ count(*)
into N_Count
from T_P_BI_HDAY_SUB a
where a.C_HDay_Code = C_Hday
and a.D_HDay >= D_Start
and a.D_HDay < D_End
and a.c_Date_Type = 'H'
and a.N_Check_State = 1;
if (N_Count > 0) then
D_End := D_Start;
D_Start := D_End - N_Count;
D_Return := D_Start;
else
exit; /*退出*/
end if;
end if;
end;
end loop;
end if;
if ('DW' = C_Type) and (N_Interval_Day>0) then
N_Count:=1;
while (true) loop
exit when N_Count = 0;
select /*+RESULT_CACHE*/ count(*)
into N_Count
from T_P_BI_HDAY_SUB a
where a.C_HDay_Code = C_Hday
and a.D_HDay = D_Return
and a.c_Date_Type = 'H'
and a.N_Check_State = 1;
if N_Count!=0 then
D_Return:=D_Return+1;
end if;
end loop;
end if;
end if;
return D_Return;
end;
END PKG_FUN_GETDAY_HDAY;
3.检验
CN:基准日期(以哪个国家进行注明)DATE ‘2023-10-08’:你要检验的日期
-1:代表去取前一日日期
‘W’:只取前面‘-1’也就是前一日的工作日
SELECT PKG_FUN_GETDAY_HDAY.GETDAY_HDAY('CN', DATE '2023-10-08', -1, 'W') AS TEST_DATA FROM TEST_TABLE a WHERE ROWNUM<2;
运行结果:
