一、题目

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, … f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

Input

On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.

Output

for each case, you should the result of y+f(x) on a line.

二、分析

简单字符串处理

#include<iostream>
using namespace std;
int main()
{
    int T;cin>>T;
    while(T--)
    {
        int ans;
        char x;int y;cin>>x>>y;
        if(islower(x)){
            ans=-(x-'a'+1)+y;
        }else ans=x-'A'+1+y;
        cout<<ans<<endl;
    }
}