超级水,不解释,代码的处理方式减低了繁琐程度,
#include <iostream>
using namespace std;
int main(int argc, char** argv) {
int num=0;
cin>>num;
int money[6]={100,50,20,10,5,1};
for(int i=0;i<=5;i++)
{
int count=0;
count=num/money[i];
num-=money[i]*count;
cout<<count<<endl;
}
return 0;
}