文件名称是递增的,删除掉其中一部分的文件,导致递增文件缺少,通过python查找出缺少的递增文件名称
通过python,查找出缺少的递增的文件的名称:
代码如下:
import os
def find_missing_numbers(folder_path):
file_list = os.listdir(folder_path)
sorted_files = sorted(file_list)
missing_numbers = []
prev_number = None
for file_name in sorted_files:
# 提取文件名中的数字部分
number_str = file_name.split("_")[-1].split(".")[0]
if number_str.isdigit():
current_number = int(number_str)
if prev_number is not None and current_number > prev_number + 1:
# 发现缺失的递增数字
for i in range(prev_number + 1, current_number):
missing_numbers.append(i)
prev_number = current_number
return missing_numbers
# 指定要查找的文件夹路径 此处放入你要访问的文件夹
folder_path = '/path/to/your/folder'
missing_nums = find_missing_numbers(folder_path)
if len(missing_nums) == 0:
print("没有发现缺失的递增数字")
else:
print("发现缺失的递增数字:", missing_nums)
注意:我的文件是前面数字中间有个“—”,后面的数字递增,你可以稍微修改一下代码就可以用
import os
def find_missing_numbers(folder_path):
file_list = os.listdir(folder_path)
sorted_files = sorted(file_list)
missing_numbers = []
prev_number = None
for file_name in sorted_files:
# 提取文件名中的数字部分
number_str = file_name.split("_")[-1]
if number_str.isdigit():
current_number = int(number_str)
if prev_number is not None and current_number > prev_number + 1:
# 发现缺失的递增数字
for i in range(prev_number + 1, current_number):
missing_numbers.append(i)
prev_number = current_number
return missing_numbers
# 指定要查找的文件夹路径
# folder_path = '/path/to/your/folder'
folder_path = "E:/python/yoloProjectTestSmallLarge/data/VOC2028/Annotations"
missing_nums = find_missing_numbers(folder_path)
if len(missing_nums) == 0:
print("没有发现缺失的递增数字")
else:
print("发现缺失的递增数字:", missing_nums)
担心有些不知道怎么改,我将原始不带“_”的代码奉上
import os
def find_missing_numbers(folder_path):
file_list = os.listdir(folder_path)
sorted_files = sorted(file_list)
missing_numbers = []
prev_number = None
for file_name in sorted_files:
# 提取文件名中的数字部分
number_str = ''.join(filter(str.isdigit, file_name))
if number_str != '':
current_number = int(number_str)
if prev_number is not None and current_number > prev_number + 1:
# 发现缺失的递增数字
for i in range(prev_number + 1, current_number):
missing_numbers.append(i)
prev_number = current_number
return missing_numbers
# 指定要查找的文件夹路径
folder_path = '/path/to/your/folder'
missing_nums = find_missing_numbers(folder_path)
if len(missing_nums) == 0:
print("没有发现缺失的递增数字")
else:
print("发现缺失的递增数字:", missing_nums)