这个有两个方案：
1.每个都装得最满，减少瓶子容积损失

//xzlist 瓶子容积排序 tj水总体积 xzzc各个体积瓶子数
public  static void Boxjs(int tj, List<Map<String,Object>> xzlist, List<Map<String,Object>> xzzc){
        boolean flg = true;
        String xzmc1="";
        Integer xzrj1=0;
        if (tj>0) {
            for (int i = 0; i < xzlist.size(); i++) {
                Integer xzrj = (Integer) xzlist.get(i).get("xzrj");
                String xzmc = (String) xzlist.get(i).get("xzmc");
                if (tj >= xzrj) {
                    xzmc1 = xzmc;
                    xzrj1 = xzrj;
                    break;
                } else {
                    if (i == xzlist.size() - 1) {
                        xzmc1 = xzmc;
                        xzrj1 = xzrj;
                    }
                }
            }
            for (Map<String, Object> zc : xzzc
            ) {
                if (zc.get("xzmc").equals(xzmc1)) {
                    zc.put("sl", ((Integer) zc.get("sl")) + 1);
                    flg = false;
                }
            }
            if (flg) {
                Map<String, Object> map = new HashMap<>();
                map.put("xzmc", xzmc1);
                map.put("sl", 1);
                xzzc.add(map);
            }
            Boxjs(tj - xzrj1, xzlist, xzzc);
        }
    }

调用

List<Map<String,Object>> xzlist=new ArrayList<>();
        List<Map<String,Object>> xzzc=new ArrayList<>();
        Map<String, Object> map = new HashMap<>();
        map.put("xzmc", "100容积瓶子");
        map.put("xzrj",100 );
        Map<String, Object> map1 = new HashMap<>();
        map1.put("xzmc", "50容积瓶子");
        map1.put("xzrj",50 );
        Map<String, Object> map2 = new HashMap<>();
        map2.put("xzmc", "30容积瓶子");
        map2.put("xzrj",30 );
        Map<String, Object> map3 = new HashMap<>();
        map3.put("xzmc", "20容积瓶子");
        map3.put("xzrj",20 );
        Map<String, Object> map4 = new HashMap<>();
        map4.put("xzmc", "10容积瓶子 ");
        map4.put("xzrj",10);
        xzlist.add(map);
        xzlist.add(map1);
        xzlist.add(map2);
        xzlist.add(map3);
        xzlist.add(map4);

        Boxjs(151,xzlist,xzzc);
        xzzc.forEach(stm1 -> System.out.println(stm1));

2.少瓶子方案，使用最少瓶子：

    //xzlist 瓶子容积排序 tj水总体积 xzzc各个体积瓶子数
    public  static void LBoxjs(int tj, List<Map<String,Object>> xzlist, List<Map<String,Object>> xzzc){
        boolean flg = true;
        String xzmc1="";
        Integer xzrj1=0;
        if (tj>0) {
            for (int i = xzlist.size()-1; i >=0; i--) {
                Integer xzrj = (Integer) xzlist.get(i).get("xzrj");
                String xzmc = (String) xzlist.get(i).get("xzmc");
                if (tj <= xzrj) {
                    xzmc1 = xzmc;
                    xzrj1 = xzrj;
                    break;
                } else {
                    if (i ==0) {
                        xzmc1 = (String) xzlist.get(0).get("xzmc");
                        xzrj1 = (Integer) xzlist.get(0).get("xzrj");
                        break;
                    }
                }
            }
            for (Map<String, Object> zc : xzzc
            ) {
                if (zc.get("xzmc").equals(xzmc1)) {
                    zc.put("sl", ((Integer) zc.get("sl")) + 1);
                    flg = false;
                }
            }
            if (flg) {
                Map<String, Object> map = new HashMap<>();
                map.put("xzmc", xzmc1);
                map.put("sl", 1);
                xzzc.add(map);
            }
            LBoxjs(tj - xzrj1, xzlist, xzzc);
        }
    }