倍数

#include <iostream>
using namespace std;
int a, b;
int main()
{
    cin >> a >> b;
    if (a % b == 0 || b % a == 0) cout << "Sao Multiplos";
    else cout << "Nao sao Multiplos";
    return 0;
}

零食

#include <iostream>
using namespace std;
int main() {
    double priceList[6] = {0, 4.00, 4.50, 5.00, 2.00, 1.50};
    int no, num;
    scanf("%d%d", &no, &num);
    printf("Total: R$ %.2lf\n", priceList[no] * num);
    return 0;
}

三角形

#include<iostream>
#include<cmath>
using namespace std;
int main()
{
    double a,b,c;
    cin>>a>>b>>c;
    //判断三边是否可构成三角形   两边之和>第三边 两边之差的绝对值<第三边
    if(a+b>c && fabs(a-b)<c) printf("Perimetro = %.1lf",a+b+c);
    else printf("Area = %.1lf",(a+b)*c/2);
    return 0;
}

游戏时间

#include<bits/stdc++.h>
using namespace std;
int s,e;
int ans;
int main()
{
    scanf("%d%d",&s,&e);
    if(e<=s)
    {
        e=e+24;
    }
    ans=e-s;
    printf("O JOGO DUROU %d HORA(S)\n",ans);
    return 0;
}

DDD

#include<iostream>
#include<string>
using namespace std;
int main()
{
    int x;
    cin >> x ;
    int a[] ={61,71,11,21,32,19,27,31};//务必在定义数组时确保两数组对应位置相同
    string b[]={"Brasilia","Salvador","Sao Paulo","Rio de Janeiro","Juiz de Fora","Campinas",
                "Vitoria","Belo Horizonte"};
    string t="a"; //工具变量t，存在目的：确定输入的x是否在a数组中；

    int i ;
    for(i=0;i<8;i++) {
        if(x == a[i]) {
        t = b[i]; //将a与b联系起来
        break; //程序运行过程中满足if则运行break结束循环，在这里结束for循环；提高运行效率。
        }
    }
    if(t == "a")    printf("DDD nao cadastrado");
    else  cout<<t;

    return 0; 
}

• 普通解法

#include <iostream>
using namespace std;
int main()
{
    int x;
    cin>>x;
    if (x==61)   cout<< "Brasilia" <<endl;
    else if(x==71) cout<< "Salvador" <<endl;
    else if(x==11) cout<< "Sao Paulo" <<endl;
    else if(x==21) cout<< "Rio de Janeiro" <<endl;
    else if(x==32) cout<< "Juiz de Fora" <<endl;
    else if(x==19) cout<< "Campinas" <<endl;
    else if(x==27) cout<< "Vitoria" <<endl;
    else if(x==31) cout<< "Belo Horizonte" <<endl;
    else cout << "DDD nao cadastrado" <<endl;
    return 0;
}

游戏时间

#include <iostream>

using namespace std;

int main()
{
    int a, b, c, d, minute1, minute2;

    cin >> a >> b >> c >> d;
    minute1 = a * 60 + b;
    minute2 = c * 60 + d;

    int hour = 0, minute = 0;
    int dec = minute2 - minute1;

    if(dec == 0)
    {
        hour = 24;
        minute = 0;
    }
    else
    {
        if(dec < 0)       //如 22:00 到 5:00 
        {      
            dec += 24 * 60; //dec计算的是5点到22点的时间，共17小时。故应用一天的分钟(24*60)减去，才是正确经历的分钟
        }
        hour = dec / 60;
        minute = dec % 60;
    }
    cout << "O JOGO DUROU " << hour << " HORA(S) E " << minute << " MINUTO(S)";
    return 0;
}

简单排序

#include<cstdio>
#include<iostream>
using namespace std;
int main()
{
    int a,b,c;
    cin>>a>>b>>c;
    int x,y,z;
    x=max(a,max(b,c));
    y=min(a,min(b,c));
    z=a+b+c-x-y;
    cout<<y<<endl;
    cout<<z<<endl;
    cout<<x<<endl;
    cout<<endl;
    cout<<a<<endl;
    cout<<b<<endl;
    cout<<c<<endl;
    return 0;
}