一、题目描述

二、代码

#include <iostream>
using namespace std;
double bijiao(double ca,double cb,double cc)
{
	double* t = &ca;
	if(*t < cb)		t=&cb;
	if(*t < cc)		t=&cc;
	return *t;
}
int main()
{
	double a,b,c; 
	cin >> a >> b >> c; 
	cout << bijiao(a,b,c);
    return 0;
}