查看oracle数据库表上碎片

先创建个函数

FUNCTION get_space_usage1(
    owner IN VARCHAR2,
    object_name IN VARCHAR2,
    segment_type IN VARCHAR2,
    partition_name IN VARCHAR2 DEFAULT NULL) RETURN sys.DBMS_DEBUG_VC2COLL PIPELINED
    AS
        ufbl   NUMBER;
        ufby   NUMBER;
        fs1bl  NUMBER;
        fs1by  NUMBER;
        fs2bl  NUMBER;
        fs2by  NUMBER;
        fs3bl  NUMBER;
        fs3by  NUMBER;
        fs4bl  NUMBER;
        fs4by  NUMBER;
        fubl   NUMBER;
        fuby   NUMBER;
    BEGIN
        DBMS_SPACE.SPACE_USAGE(owner,object_name,segment_type,
        ufbl, ufby, fs1bl,fs1by, fs2bl,fs2by,
        fs3bl,fs3by, fs4bl,fs4by, fubl,fuby, partition_name);
        PIPE ROW('Full blocks       /MB '||TO_CHAR(fubl,  '999999999')||' '||TO_CHAR(fuby  /1048576,'999999999'));
        PIPE ROW('Unformatted blocks/MB '||TO_CHAR(ufbl,  '999999999')||' '||TO_CHAR(ufby  /1048576,'999999999'));
        PIPE ROW('Free Space      0-25% '||TO_CHAR(fs1bl, '999999999')||' '||TO_CHAR(fs1by /1048576,'999999999'));
        PIPE ROW('Free Space     25-50% '||TO_CHAR(fs2bl, '999999999')||' '||TO_CHAR(fs2by /1048576,'999999999'));
        PIPE ROW('Free Space     50-75% '||TO_CHAR(fs3bl, '999999999')||' '||TO_CHAR(fs3by /1048576,'999999999'));
        PIPE ROW('Free Space    75-100% '||TO_CHAR(fs4bl, '999999999')||' '||TO_CHAR(fs4by /1048576,'999999999'));
    END get_space_usage1;

使用方法

col COLUMN_VALUE for a60
SELECT * FROM TABLE(get_space_usage1(user,'T2','TABLE'));

效果

略有些复杂。
但是对空块好像判断不对