目录
需求与分析
具体实现
牌类定义
房间类定义
初步测试
启动游戏
运行案例
需求与分析
需求
- 总共有54张牌
- 点数:"3","4","5","6","7","8","9","10","J","Q","K","A","2"
- 花色:"♠","♥","♣","♦"
- 大小王:"👲","🃏"
- 斗地主:发出51张牌,剩下3张作为底牌
分析实现
- 在启动游戏房间的时候,应该提前准备好54张牌
- 接着,需要完成洗牌、发牌、对牌排序、看牌
具体实现
牌类定义
package user.Collection;
public class Card {
private String number;
private String color;
//每张牌是存在牌值大小的
private int size; //0 1 2 ...
public Card() {
}
public Card(String number, String color, int size) {
this.number = number;
this.color = color;
this.size = size;
}
public String getNumber() {
return number;
}
public void setNumber(String number) {
this.number = number;
}
public String getColor() {
return color;
}
public void setColor(String color) {
this.color = color;
}
public int getSize() {
return size;
}
public void setSize(int size) {
this.size = size;
}
@Override
public String toString() {
return number + color;
}
}
房间类定义
package user.Collection;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.List;
public class Room {
//首先必须有一副牌
private List<Card> allCards = new ArrayList<>();
public Room(){
//1.做出54张牌,存入到集合allCards
//a.所有牌的点数
String[] numbers = {"3","4","5","6","7","8","9","10","J","Q","K","A","2"};
//b.所有牌的花色
String[] colors = {"♠","♥","♣","♦"};
int size = 0; //表示每张牌的牌值大小
//c.遍历点数,再遍历花色,组织牌
for(String number:numbers){
//number = "3"
size++; //1 2 3 ......
for(String color:colors){
//得到一张牌
Card d = new Card(number,color,size);
allCards.add(d); //存入牌库
}
}
//单独存入大小王
Card d1 = new Card("","🃏",++size); //小王
Card d2 = new Card("","👲",++size); //大王
Collections.addAll(allCards,d1,d2);
}
}
初步测试
在Room类中加一下输出语句:(已重写Card类的toString方法)
在主程序中运行:
运行结果:
启动游戏
在Room类中编写启动游戏的方法,再调用
public void start() {
//1.洗牌
Collections.shuffle(allCards);
System.out.println("洗牌后:" + allCards);
//2.发牌,发给三个玩家 还是使用List集合
List<Card> MegMarch = new ArrayList<>();
List<Card> JoMarch = new ArrayList<>();
List<Card> BethMarch = new ArrayList<>();
//正式发牌给这三个玩家,依次发出51张牌,剩余三张作为底牌
for(int i = 0;i < allCards.size();i++){
Card c = allCards.get(i);
//判断发牌给谁
if(i % 3 == 0){
//发牌给梅格
MegMarch.add(c);
}else if(i % 3 == 1){
//发牌给乔
JoMarch.add(c);
}else if(i % 3 == 2){
//发牌给贝丝
BethMarch.add(c);
}
}
//3.对三个玩家的牌进行排序
sortCards(MegMarch);
sortCards(JoMarch);
sortCards(BethMarch);
//4.看牌
System.out.println("梅格 :" + MegMarch);
System.out.println("乔 :" + JoMarch);
System.out.println("贝丝 :" + BethMarch);
List<Card> lastThreeCards = allCards.subList(allCards.size() - 3,allCards.size());
System.out.println("底牌 :" + lastThreeCards);
//假设乔抢到了地主
JoMarch.addAll(lastThreeCards);
sortCards(JoMarch);
System.out.println("乔抢到地主后:" + JoMarch);
}
private void sortCards(List<Card> cards) {
Collections.sort(cards, new Comparator<Card>() {
@Override
public int compare(Card o1, Card o2) {
return o2.getSize() - o1.getSize(); //降序排序
}
});
}
运行案例
END
学习自:黑马程序员——JavaSE课程