基础信息获取：

要闻url：https://www.gov.cn/yaowen/liebiao/home.htm

下一页的url：https://www.gov.cn/yaowen/liebiao/home_1.htm

基础代码：

import re
import openpyxl
import requests
from lxml import etree
import os

def download_xinwen():
    basic_url = 'https://www.gov.cn/yaowen/liebiao/home.htm'
    for num in range(1, 5):
        print(f"Downloading:第{num}页")
        new_url = 'https://www.gov.cn/yaowen/liebiao/home_{}.htm'.format(num)
        headers = {'user-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/122.0.0.0 Safari/537.36'}
        response = requests.get(new_url, headers=headers)
        response.encoding = 'utf8'
        # print(response.text)
        html = etree.HTML(response.text)
        xinwen_info = html.xpath('//div//li//h4/a/text()')
        xinwen_lianjie = html.xpath('//h4/a/@href')
        for describe, download_url in zip(xinwen_info, xinwen_lianjie):
            print("新闻标题:", describe, "|", "新闻链接:", download_url)
            # if "https" not in download_url:
            #     original_str = download_url
            #     new_str = original_str.replace("./", "")
            #     download_url ="https://www.gov.cn/yaowen/liebiao/" + new_str
            #     # print(download_url)
            # print("新闻标题:", describe, "|", "新闻链接:", download_url)



            # new_xinwen_url = download_url.split('.')[-1]
            # print(new_xinwen_url)


download_xinwen()

返回：

 可以看到有的url链接爬取下来之后不是全路径，针对这个问题加上如下代码：

在for循环内加上判断，如果https不在url列表里，说明这个url不是全路径，将./全部替换成空字符，再拼接下基础url，这样遍有了url全路径

             if "https" not in download_url:
                 original_str = download_url
                 new_str = original_str.replace("./", "")
                 download_url ="https://www.gov.cn/yaowen/liebiao/" + new_str
                
             print("新闻标题:", describe, "|", "新闻链接:", download_url)

再次运行调试：

url连接都是全路径了