【JS逆向学习】猿人学第六题 js混淆回溯

逆向目标

网址：https://match.yuanrenxue.cn/match/6
接口：https://match.yuanrenxue.cn/api/match/6
参数：payload(m、q)

逆向过程

老规矩，先来分析网络请求，加密的地方一目了然，没什么可多说的，直接进行下一步的分析
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逆向分析

启动器跟栈进入打个断点然后翻页
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断点断住了

t = Date.parse(new Date());
var list = {
    "page": window.page,
    "m": r(t, window.o),
    "q": window.i += window.o + '-' + t + "|",
};
window.o += 1;

我们直接进到加密js文件delect.js，然后来分析一下这个文件内容
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如上截图，整个js文件就这么几块内容，最后一个红框内容一看就是我们的加密函数，中间那个就是一个webpack的对象形式，还有对webpack不太熟悉的朋友可以去阅读下这篇文章【JS逆向学习】36kr登陆逆向案例（webpack），里面有对webpack做了详细介绍并给出了具体案例，最上面那个红框里的内容看起来就是一堆的笑脸符号，其实就是AAEncode加密/解密，遇到这种没见过的加密字符百度搜索就行了，这里给出一个AAEncode加密/解密的在线网站
AAEncode加密/解密，我们把第一个红框内的内容解密一下看是个什么东西
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可以看到这一大坨就只是做了一个变量赋值window.o=1;，先不管它我们继续跟栈分析

function r(param1, param2) {
    if (window.o >= 6) {
        alert('不要戳这么多下，人家好痛嘛~');
        location.reload();
    }
    return z(param1, param2);
}

window.o就是翻页累计的变量，超过 6 次就会重新加载网页，再来看加密的参数

function z(pwd, time) {
    var n = _n("jsencrypt");
    var g = (new n);
    var r = g.encode(pwd, time);
    return r;
}

pwd 就是13位的时间戳，time 就是页数，加密函数和加密参数都清楚了，既然是webpack 而且只有两个模块，我们就直接全部扣，然后给个值本地调用加密函数看下结果

/Users/rookie/dev/jsprojects/yuanrenxue/Chatper6/test.js:2557
                ASN1.prototype.getHexStringValue = function() {
                                                 ^

ReferenceError: ASN1 is not defined

奇怪了，代码里面明明有定义这个变量
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我们先补上window = global; 然后输出一下window 看看

window 为空，这就怪了，肯定有地方对window做了赋值或删除操作，我们先全局搜索一下看

自执行函数对window做了重新赋值操作，作者巧妙利用了浏览器环境和node环境的区别埋了个雷，在浏览器下执行window={}实际不会生效的，但是在node 环境中做window={}操作则会生效，我们把这行代码注释，重新打印观察下window

window:  <ref *1> Object [global] {
  global: [Circular *1],
  queueMicrotask: [Function: queueMicrotask],
  clearImmediate: [Function: clearImmediate],
  setImmediate: [Function: setImmediate] {
    [Symbol(nodejs.util.promisify.custom)]: [Getter]
  },
  structuredClone: [Getter/Setter],
  clearInterval: [Function: clearInterval],
  clearTimeout: [Function: clearTimeout],
  setInterval: [Function: setInterval],
  setTimeout: [Function: setTimeout] {
    [Symbol(nodejs.util.promisify.custom)]: [Getter]
  },
  atob: [Getter/Setter],
  btoa: [Getter/Setter],
  performance: [Getter/Setter],
  fetch: [AsyncFunction: fetch],
  crypto: [Getter],
  window: [Circular *1],
  navigator: {}
}

可以看到，这个时候window是有值的，然后看到又报了其他的错

Message too long for RSA

继续分析代码发现了一大坨jsfuck 混淆后的代码

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直接拷贝到控制台执行一下，就是一个false

xe = false

直接替换下，然后再次执行代码，发现有结果了

55oooAObwblpKTvAWBcmMINgCzert2%2BSoeGzJ2CV9XzdzsMpWK9WNJlKOj%2FDzXor7TvLUKMguBnnK0thBNq%2BrZrBtokWfWJze8dvmB%2FUpTrmLTKnQvCHfKuoMuBkUd%2FZt4LzQykZCDlz9Fwl69VAoxJMak8c0SxvqXv0%2FdeC8GI%3D

到这里m参数的加密已经分析结束了，我们继续看q

"q": window.i += window.o + '-' + t + "|"

再结合网络请求来看q是做了拼接了

q: 1-1710235684000|2-1710235690000|

但是我们每次用于加密的是没有拼接

在这里插入图片描述
至此两个参数的加密分析都完成了

逆向结果

源码，需要的自取猿人学第六题源码
在这里插入图片描述