【C/PTA —— 14.结构体1（课外实践）】

news2024/9/24 23:30:06

C/PTA —— 14.结构体1（课外实践）

一.函数题
- 6-1 选队长
- 6-2 按等级统计学生成绩
- 6-3 学生成绩比高低
- 6-4 综合成绩
- 6-5 利用“选择排序算法“对结构体数组进行排序
- 6-6 结构体的最值
- 6-7 复数相乘运算
二.编程题
- 7-5 一帮一
- 7-6 考试座位号

一.函数题

6-1 选队长

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void showCaptain(TeamMember team[], int n)
{
    TeamMember max;
    max = team[0];
    for (int i = 1; i < n; i++)
    {
        if (max.ability < team[i].ability)
            max = team[i];
    }
    printf("%d %s %s %s %.2lf", max.id, max.lastname,max.firstname, max.sex, max.ability);
}

6-2 按等级统计学生成绩

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int set_grade(struct student* p, int n)
{
    int count = 0;
    for (int i = 0; i < n; i++)
    {
        if (p[i].score >= 85 && p[i].score <= 100)
            p[i].grade = 'A';
        if (p[i].score >= 70 && p[i].score <= 84)
            p[i].grade = 'B';
        if (p[i].score >= 60 && p[i].score <= 69)
            p[i].grade = 'C';
        if (p[i].score >= 0 && p[i].score <= 59)
        {
            p[i].grade = 'D';
            count++;
        }     
    }
    return count;
}

6-3 学生成绩比高低

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int compareScore(const struct Student* s1, const struct Student* s2)
{
    if ((s1->C + s1->English) > (s2->C + s2->English))
        return 1;
    if ((s1->C + s1->English) < (s2->C + s2->English))
        return -1;
    if ((s1->C + s1->English) == (s2->C + s2->English))
    {
        if (s1->C > s2->C)
            return 1;
        if (s1->C < s2->C)
            return -1;
        if (s1->C == s2->C)
            return 0;
    }
}

6-4 综合成绩

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double getAverage(Applicant* a)
{
    double sum = 0.0;
    sum = a->computational * 1.0 * 0.4 + a->humanistic * 1.0 * 0.5 + a->logical * 1.0 * 0.3 + a->presentation * 1.0 * 0.6 + a->scientific * 1.0 * 0.8;
    return sum;
}

6-5 利用“选择排序算法“对结构体数组进行排序

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int min_idx = p1->score;
for (p2 = p1 + 1; p2 < pData + n; p2++)
{
    if (p2->score > min_idx)
    {
        min_idx = p2->score;
        p = p2;
    }
}
if (min_idx != p1->score)
{
    num = p1->num;
    score = p1->score;
    p1->num = p->num;
    p1->score = p->score;
    p->num = num;
    p->score = score;
}

6-6 结构体的最值

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ST* MaxST(ST d[], int n, int k)
{
    ST* max = NULL;
    for (int i = 0; i < n; i++)
    {
        if (d[i].gender == k && (max == NULL || max->scored < d[i].scored))
        {
            max = &d[i];
        }
    }
    return max;
}

6-7 复数相乘运算

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PLEX multi(PLEX a, PLEX b)
{
    PLEX product;
    product.re = a.re * b.re - a.im * b.im;
    product.im = a.re * b.im + a.im * b.re;
    return product;
}

二.编程题

7-5 一帮一

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#include<stdio.h>
#include<string.h>

struct student
{
    int a;
    char name[20];
};

struct student1
{
    int b;
    char name1[20];
};

int main()
{
    struct student  s1[50];
    struct student1 s2[50];
    struct student1 s3[50];

    int i, n, j = 0, t = 0, c, d;
    scanf("%d", &n);
    for (i = 0; i < n; i++)
    {
        scanf("%d %s", &s1[i].a, s1[i].name);
    }

    for (i = 0; i < n; i++)
    {
        if (s1[i].a == 1)
        {
            s2[j].b = i;
            strcpy(s2[j].name1, s1[i].name);
            j++;
        }
        if (s1[i].a == 0)
        {
            s3[t].b = i;
            strcpy(s3[t].name1, s1[i].name);
            t++;
        }
    }

    c = n / 2 - 1, d = n / 2 - 1;
    j = 0, t = 0;
    for (i = 0; i < n / 2; i++)
    {
        if (s3[j].b < s2[t].b)
        {
            printf("%s %s\n", s3[j].name1, s2[c].name1);
            j++;
            c--;
        }
        else
        {
            printf("%s %s\n", s2[t].name1, s3[d].name1);
            t++;
            d--;
        }
    }
    return 0;
}

7-6 考试座位号

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#include<stdio.h>
struct student
{
	char number[17];
	int s;
	int k;
};

int main()
{
	int N = 0;
	scanf("%d", &N);
	struct student stu[1001] = {0};
	for (int i = 0; i < N; i++)
	{
		scanf("%s %d %d", stu[i].number, &stu[i].s, &stu[i].k);
	}
	int n = 0;
	scanf("%d", &n);
	int ret = 0;
	for (int i = 0; i < n; i++)
	{
		scanf("%d", &ret);
		int j = 0;
		for (j = 0; j < N; j++)
		{
			if (ret == stu[j].s)
			{
				printf("%s %d\n", stu[j].number, stu[j].k);
			}
		}
	}
	
	return 0;
}