顺着日期

public class Main {
	public static void main(String[] args) {
		int res = 0;
		//2022年
		int[] days = new int[] {31,28,31,30,31,30,31,31,30,31,30,31};
		//31,28,31,30,31,30,31,31,30,31,30,31
		//一三五七八十腊
		
		//构造2022年每一天的日期yyyymmdd
		StringBuffer date = new StringBuffer("2022");
		for(int m=1;m<=12;m++) {
			if(m<10) {
				date.append(0);
			}
			date.append(m);
			for(int d=1;d<=days[m-1];d++) {
				if(d<10) {
					date.append(0);
				}
				date.append(d);
				if(isLegal(date.toString())) {
					res++;
				}
				date.delete(6, 8);//20220101 -> 202201
			}
			date.delete(4, 8);//202201 -> 2022
		}
		System.out.println(res);
	 }
	public static boolean isLegal(String date) {
		//20220101
		//202201
		int l = 0;
		int n = date.length();
		while(l<=n-3) {
			int t1 = (int)Integer.valueOf(date.substring(l,l+1));//2
			int t2 = (int)Integer.valueOf(date.substring(l+1,l+2));//0
			int t3 = (int)Integer.valueOf(date.substring(l+2,l+3));//2
			if(t1 == (t2-1) && t2 == (t3-1)) {
				return true;
			}
			l++;
		}
		return false;
	}
}