我的需求是跳转到第三方网站，看官方是写了如何跳转站内路由，不符合我的要求，在csdn发现了一篇文章，我贴一下代码

 

<template>
                                <Table border :columns="ReportColumns" :data="ReportData">
                                    <template #name="{ row }">
                                        <strong>{{ row.name }}</strong>
                                    </template>
                                    <template #action="{ row, index }">

<!--                                        <a href="http://wwww.baidu.com/" target="_blank">view</a>-->
<!--                                        <Button type="primary" size="small" style="margin-right: 5px"  target="_blank" >View</Button>-->
                                        <Button type="error" size="small" @click="remove(index)">Delete</Button>
                                    </template>
                                </Table>
                            </template>

 data(){
            return{

                ReportColumns:[
                    {
                        title: '生成时间',
                        key: 'createTime',
                        width: 220
                    },
                    {
                        title: '生成用户',
                        key: 'creator',
                        width: 200
                    },
                    {
                        title:'报告地址',
                        key:'reportUrl',
                        width: 800,
                        render: (h, params) => {
                            return h('span',
                                {
                                    domProps: {
                                        innerHTML: "<a href='" + params.row.reportUrl + "' target='_blank'>" + params.row.reportUrl + '</a>'
                                    }
                                }
                            )
                        }

                    },
                    {
                        title: '操作',
                        slot: 'action',
                    }
                ],

后端接口报文格式

{
    "ret": true,
    "code": 0,
    "msg": "查询成功",
    "content": [
        {
            "id": 522,
            "reportId": 2561,
            "creator": "李朝阳",
            "createTime": "2023-11-03 12:05:00",
            "reportUrl":"http://192.168.0.1:1111/view/project/5f1e8e97b6e123455555" 
        },
        {
           
            "id": 523,
            "reportId": 2562,
            "creator": "白克玲",
            "createTime": "2023-10-03 11:25:00",
            "reportUrl":"https://blog.csdn.net/qq_42772400/article/details/128386185"
        }
    ]
}

原贴地址

iview table实现通过render实现点击跳转到相应的网址_iview页面跳转-CSDN博客