MySql时间查询
MySql查询当前时间
- 查询 年-月-日 时:分:秒
select now()
- 查询 年-月-日
select DATE(CURDATE())
- 查询 年-月
select date_format(NOW(),'%Y-%m')
- 查询当前年
select YEAR(CURDATE())
- 查询当前月
select MONTH(CURDATE())
- 查询当前日
select DAYOFMONTH(NOW())
- 查询当前星期几
select dayofweek(NOW()) -1
- 查询当前季度
select QUARTER(now())
- 查询 时:分:秒
select current_time()
- 万能公式:DATE_FORMAT
select DATE_FORMAT(now(),'%Y-%m-%d %h:%i:%s')
MySql查询上一年、上一个月、上一个星期…
-
查询昨天的数据
select * from test as 'time' where time.update_time <DATE_SUB(CURDATE(), INTERVAL 1 DAY)
-
查询当前这周的数据
select * from test as 'time' where time.update_time<DATE_SUB(CURDATE(), INTERVAL 0 WEEK)
select * FROM test as 'time' where YEARWEEK(date_format(time.update_time,’%Y-%m-%d’)) = YEARWEEK(now())
-
查询上一周的数据
select * from test as 'time' where time.update_time<DATE_SUB(CURDATE(), INTERVAL 1 WEEK)
select * FROM test as 'time' WHERE YEARWEEK(date_format(time.update_time,’%Y-%m-%d’)) = YEARWEEK(now())-1
-
查询上一个月的数据
select * from test as 'time' where time.update_time<DATE_SUB(CURDATE(), INTERVAL 1 MONTH)
-
查询近两个月的数据(INTERVAL后面的数字改一下就可以了)
select * from test as 'time' where time.update_time<DATE_SUB(CURDATE(), INTERVAL 2 MONTH)
-
查询上一年的数据
select * from test as 'time' where time.update_time<DATE_SUB(CURDATE(), INTERVAL 1 YEAR)
-
查询距离当前现在6个月的数据
select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();
MySql查询本年、本月、本周…
-
查询今天的数据
select * from test as time where to_days(time.update_time ) =to_days(now());
-
查询本周的数据
select * FROM test as time WHERE YEARWEEK(date_format(time.update_time ,'%Y-%m-%d')) = YEARWEEK(now());
-
查询本月的数据
select * FROM test as time WHERE DATE_FORMAT(time.update_time , '%Y%m' ) = DATE_FORMAT( CURDATE( ) , '%Y%m' )
-
查询本季度的数据
select * from test as time where QUARTER(time.update_time)=QUARTER(now());
-
查询本年的数据
select * from test as time where YEAR(time.update_time)=YEAR(NOW());
实战:生成这样的一个数据表,根据月份来输出值
有两个关键的数据,一个是月份,一个是数据,我们要的效果,每个月累加(比如6月份有一个人,但7月份没有,但是是累加的,所以7月份有一个,12月份新增三个,所以总共是4)
思考:
第一点:月份:要通过本月来向前面递减,重点用UNION
连接函数
-- 近1个月
SELECT DATE_FORMAT( CURDATE( ), '%Y-%m' ) AS `month` UNION
-- 近2个月
SELECT DATE_FORMAT( ( CURDATE( ) - INTERVAL 1 MONTH ), '%Y-%m' ) AS `month` UNION
-- 近3个月
SELECT DATE_FORMAT( ( CURDATE( ) - INTERVAL 2 MONTH ), '%Y-%m' ) AS `month` UNION
SELECT DATE_FORMAT( ( CURDATE( ) - INTERVAL 3 MONTH ), '%Y-%m' ) AS `month` UNION
SELECT DATE_FORMAT( ( CURDATE( ) - INTERVAL 4 MONTH ), '%Y-%m' ) AS `month` UNION
-- 近N个月,N等于"INTERVAL 5 MONTH"中间的数值`5`加`1`,此处N=6
SELECT DATE_FORMAT( ( CURDATE( ) - INTERVAL 5 MONTH ), '%Y-%m' ) AS `month`
整理一下,因为后续我们还连接数据,所以要用v来指代这个数据
SELECT CONCAT(RIGHT(v.`month`,2),'月') AS `time`
FROM
(
-- 近1个月
SELECT DATE_FORMAT( CURDATE( ), '%Y-%m' ) AS `month` UNION
-- 近2个月
SELECT DATE_FORMAT( ( CURDATE( ) - INTERVAL 1 MONTH ), '%Y-%m' ) AS `month` UNION
-- 近3个月
SELECT DATE_FORMAT( ( CURDATE( ) - INTERVAL 2 MONTH ), '%Y-%m' ) AS `month` UNION
SELECT DATE_FORMAT( ( CURDATE( ) - INTERVAL 3 MONTH ), '%Y-%m' ) AS `month` UNION
SELECT DATE_FORMAT( ( CURDATE( ) - INTERVAL 4 MONTH ), '%Y-%m' ) AS `month` UNION
-- 近N个月,N等于"INTERVAL 5 MONTH"中间的数值`5`加`1`,此处N=6
SELECT DATE_FORMAT( ( CURDATE( ) - INTERVAL 5 MONTH ), '%Y-%m' ) AS `month`
)
AS v
第二点:数据:计算近六个月的数据(如下)
SELECT DATE_FORMAT(a.create_time, '%Y-%m') AS `month`,COUNT( * ) AS `count`
FROM `user` AS a
-- 计算近六个月的时间
WHERE DATE_FORMAT(a.create_time, '%Y-%m') > DATE_FORMAT(DATE_SUB(CURDATE(), INTERVAL 6 MONTH ), '%Y-%m')
-- 补充查询匹配条件
AND a.is_deleted = 1
GROUP BY `month`
但是这样是不对的,这个是分别查询六个月的数据,不是累加的(需要这种的朋友上面代码自取),所以我们要改一下思路
SELECT DATE_FORMAT(( CURDATE( ) - INTERVAL 0 MONTH ), '%Y-%m') AS `month`,COUNT( * ) AS `count`
FROM `user` AS a
-- 计算12月及其之前的时间 (现在2022年12月份 DATE_FORMAT(( CURDATE( ) - INTERVAL 1 MONTH ), '%Y-%m') = 2022-11)
-- 这是是需要计算 一月份之前,要包含12月份
WHERE DATE_FORMAT(a.create_time, '%Y-%m') < DATE_FORMAT(( CURDATE( ) - INTERVAL -1 MONTH ), '%Y-%m')
-- 补充查询匹配条件
AND a.is_deleted = 1
好了,但这只有一条数据,我们需要再累加一下
SELECT DATE_FORMAT(( CURDATE( ) - INTERVAL 0 MONTH ), '%Y-%m') AS `month`,COUNT( * ) AS `count`
FROM `user` AS a
-- 计算12月及其之前的时间 (现在2022年12月份 DATE_FORMAT(( CURDATE( ) - INTERVAL 1 MONTH ), '%Y-%m') = 2022-11)
-- 这是是需要计算 一月份之前,要包含12月份
WHERE DATE_FORMAT(a.create_time, '%Y-%m') < DATE_FORMAT(( CURDATE( ) - INTERVAL -1 MONTH ), '%Y-%m')
-- 补充查询匹配条件
AND a.is_deleted = 1 AND a.jurisdiction = 2 UNION
-- 下面都是cv了,sql没想到什么好的办法,但在mybatis中可以优化,之后我会讲到
SELECT DATE_FORMAT(( CURDATE( ) - INTERVAL 1 MONTH ), '%Y-%m') AS `month`,COUNT( * ) AS `count`
FROM `user` AS a
WHERE DATE_FORMAT(a.create_time, '%Y-%m') < DATE_FORMAT(( CURDATE( ) - INTERVAL 0 MONTH ), '%Y-%m')
AND a.is_deleted = 1 AND a.jurisdiction = 2 UNION
SELECT DATE_FORMAT(( CURDATE( ) - INTERVAL 2 MONTH ), '%Y-%m') AS `month`,COUNT( * ) AS `count`
FROM `user` AS a
WHERE DATE_FORMAT(a.create_time, '%Y-%m') < DATE_FORMAT(( CURDATE( ) - INTERVAL 1 MONTH ), '%Y-%m')
AND a.is_deleted = 1 AND a.jurisdiction = 2 UNION
SELECT DATE_FORMAT(( CURDATE( ) - INTERVAL 3 MONTH ), '%Y-%m') AS `month`,COUNT( * ) AS `count`
FROM `user` AS a
WHERE DATE_FORMAT(a.create_time, '%Y-%m') < DATE_FORMAT(( CURDATE( ) - INTERVAL 2 MONTH ), '%Y-%m')
AND a.is_deleted = 1 AND a.jurisdiction = 2 UNION
SELECT DATE_FORMAT(( CURDATE( ) - INTERVAL 4 MONTH ), '%Y-%m') AS `month`,COUNT( * ) AS `count`
FROM `user` AS a
WHERE DATE_FORMAT(a.create_time, '%Y-%m') < DATE_FORMAT(( CURDATE( ) - INTERVAL 3 MONTH ), '%Y-%m')
AND a.is_deleted = 1 AND a.jurisdiction = 2 UNION
SELECT DATE_FORMAT(( CURDATE( ) - INTERVAL 5 MONTH ), '%Y-%m') AS `month`,COUNT( * ) AS `count`
FROM `user` AS a
WHERE DATE_FORMAT(a.create_time, '%Y-%m') < DATE_FORMAT(( CURDATE( ) - INTERVAL 4 MONTH ), '%Y-%m')
AND a.is_deleted = 1 AND a.jurisdiction = 2
把之前的结合一下
SELECT IFNULL( b.count, 0 ) AS `count`,CONCAT(RIGHT(v.`month`,2),'月') AS `time`
FROM
(
-- 近1个月
SELECT DATE_FORMAT( CURDATE( ), '%Y-%m' ) AS `month` UNION
-- 近2个月
SELECT DATE_FORMAT( ( CURDATE( ) - INTERVAL 1 MONTH ), '%Y-%m' ) AS `month` UNION
-- 近3个月
SELECT DATE_FORMAT( ( CURDATE( ) - INTERVAL 2 MONTH ), '%Y-%m' ) AS `month` UNION
SELECT DATE_FORMAT( ( CURDATE( ) - INTERVAL 3 MONTH ), '%Y-%m' ) AS `month` UNION
SELECT DATE_FORMAT( ( CURDATE( ) - INTERVAL 4 MONTH ), '%Y-%m' ) AS `month` UNION
-- 近N个月,N等于"INTERVAL 5 MONTH"中间的数值`5`加`1`,此处N=6
SELECT DATE_FORMAT( ( CURDATE( ) - INTERVAL 5 MONTH ), '%Y-%m' ) AS `month`
)
AS v LEFT JOIN
(
SELECT DATE_FORMAT(( CURDATE( ) - INTERVAL 0 MONTH ), '%Y-%m') AS `month`,COUNT( * ) AS `count`
FROM `user` AS a
-- 计算12月及其之前的时间 (现在2022年12月份 DATE_FORMAT(( CURDATE( ) - INTERVAL 1 MONTH ), '%Y-%m') = 2022-11)
-- 这是是需要计算 一月份之前,要包含12月份
WHERE DATE_FORMAT(a.create_time, '%Y-%m') < DATE_FORMAT(( CURDATE( ) - INTERVAL -1 MONTH ), '%Y-%m')
-- 补充查询匹配条件
AND a.is_deleted = 1 AND a.jurisdiction = 2 UNION
-- 下面都是cv了,sql没想到什么好的办法,但在mybatis中可以优化,之后我会讲到
SELECT DATE_FORMAT(( CURDATE( ) - INTERVAL 1 MONTH ), '%Y-%m') AS `month`,COUNT( * ) AS `count`
FROM `user` AS a
WHERE DATE_FORMAT(a.create_time, '%Y-%m') < DATE_FORMAT(( CURDATE( ) - INTERVAL 0 MONTH ), '%Y-%m')
AND a.is_deleted = 1 AND a.jurisdiction = 2 UNION
SELECT DATE_FORMAT(( CURDATE( ) - INTERVAL 2 MONTH ), '%Y-%m') AS `month`,COUNT( * ) AS `count`
FROM `user` AS a
WHERE DATE_FORMAT(a.create_time, '%Y-%m') < DATE_FORMAT(( CURDATE( ) - INTERVAL 1 MONTH ), '%Y-%m')
AND a.is_deleted = 1 AND a.jurisdiction = 2 UNION
SELECT DATE_FORMAT(( CURDATE( ) - INTERVAL 3 MONTH ), '%Y-%m') AS `month`,COUNT( * ) AS `count`
FROM `user` AS a
WHERE DATE_FORMAT(a.create_time, '%Y-%m') < DATE_FORMAT(( CURDATE( ) - INTERVAL 2 MONTH ), '%Y-%m')
AND a.is_deleted = 1 AND a.jurisdiction = 2 UNION
SELECT DATE_FORMAT(( CURDATE( ) - INTERVAL 4 MONTH ), '%Y-%m') AS `month`,COUNT( * ) AS `count`
FROM `user` AS a
WHERE DATE_FORMAT(a.create_time, '%Y-%m') < DATE_FORMAT(( CURDATE( ) - INTERVAL 3 MONTH ), '%Y-%m')
AND a.is_deleted = 1 AND a.jurisdiction = 2 UNION
SELECT DATE_FORMAT(( CURDATE( ) - INTERVAL 5 MONTH ), '%Y-%m') AS `month`,COUNT( * ) AS `count`
FROM `user` AS a
WHERE DATE_FORMAT(a.create_time, '%Y-%m') < DATE_FORMAT(( CURDATE( ) - INTERVAL 4 MONTH ), '%Y-%m')
AND a.is_deleted = 1 AND a.jurisdiction = 2
AND a.is_deleted = 1 AND a.jurisdiction = 2
) AS b
ON v.`month` = b.`month`
GROUP BY `time` ORDER BY `time` ASC
放入mybatis中优化一下
实体类:
@Data
@Accessors(chain = true)
@AllArgsConstructor
@NoArgsConstructor
public class PeopleCountVO {
private Integer count;
private String time;
private Integer jurisdiction;
private List<Integer> math;
}
xml:根据math的数据动态的修改,比如math=[1,2,3,4,5,6,7,8,9,10,11,12],就是查询12个月的数据
<select id="peopleCount" parameterType="com.zhao.pojo.vo.PeopleCountVO" resultType="com.zhao.pojo.vo.PeopleCountVO">
SELECT IFNULL( b.count, 0 ) AS `count`,v.`month` AS `time`
FROM
(
-- 查询 近六个月
<foreach collection="people.math" separator=" UNION " item="item">
SELECT DATE_FORMAT( ( CURDATE( ) - INTERVAL #{item} - 1 MONTH ), '%Y-%m' ) AS `month`
</foreach>
)
AS v LEFT JOIN
(
<foreach collection="people.math" separator=" UNION " item="item">
SELECT DATE_FORMAT(( CURDATE( ) - INTERVAL #{item}-1 MONTH ), '%Y-%m') AS `month`,COUNT( * ) AS `count`
FROM `user` AS a
-- 小于符号 在xml中会报错 使用 < 转义一下
WHERE DATE_FORMAT(a.create_time, '%Y-%m') < DATE_FORMAT(( CURDATE( ) - INTERVAL #{item}-2 MONTH ), '%Y-%m')
-- 补充查询匹配条件
AND a.is_deleted = 1 AND a.jurisdiction = #{people.jurisdiction}
</foreach>
) AS b
ON v.`month` = b.`month`
GROUP BY `time` ORDER BY `time` ASC
</select>