1. 网址

aHR0cHM6Ly9pdC5zem9ubGluZS5uZXQvc2h1eml6aG9uZ2d1by8yMDIzMDMyOS8yMDIzMDM3ODAzNDAuaHRtbA==

2. 抓包

猜想：从图中对比发现取第一次请求返回的Set-Cookie作为第二次请求的cookies，不过需要把Set-Cookie中的secret-100（此时注意int和str类型的来回转换），名称变为r，把Set-Cookie中的token变为t

3. 第一次请求返回：

<script language="javascript" type="text/javascript">
	eval(function(p, a, c, k, e, d) {
		e = function(c) {
			return (c < a ? "": e(parseInt(c / a))) + ((c = c % a) > 35 ? String.fromCharCode(c + 29) : c.toString(36))
		};
		if (!''.replace(/^/, String)) {
			while (c--) d[e(c)] = k[c] || e(c);
			k = [function(e) {
				return d[e]
			}];
			e = function() {
				return '\\w+'
			};
			c = 1;
		};
		while (c--) if (k[c]) p = p.replace(new RegExp('\\b' + e(c) + '\\b', 'g'), k[c]);
		return p;
	} ('p b(j){1 7=j+"=";1 a=3.4.o(\';\');u(1 i=0;i<a.9;i++){1 c=a[i].s();f(c.q(7)==0)g c.v(7.9,c.9)}g""}1 6=b("6");1 5=B(b("5"));f(6==""||5==""){D("8=8; ",C)}x{1 k=5-y;3.4="6=; d=e, m l n 2:2:2 h;";3.4="5=; d=e, m l n 2:2:2 h;";3.4="t="+6+";";3.4="r="+k+";";A.8.z(w)}', 40, 40, '|var|00|document|cookie|secret|token|name|location|length|ca|getCookie||expires|Thu|if|return|UTC||cname|random|Jan|01|1970|split|function|indexOf||trim||for|substring|true|else|100|reload|window|parseInt|3000|setTimeout'.split('|'), 0, {}))
</script>

js反混淆解密，见（https://blog.csdn.net/CaliXz/article/details/127405966）

function getCookie(cname) {
    var name = cname + "=";
    var ca = document.cookie.split(';');
    for (var i = 0; i < ca.length; i++) {
        var c = ca[i].trim();
        if (c.indexOf(name) == 0) return c.substring(name.length, c.length)
    }
    return ""
}   //这段代码的作用是获取指定名称的cookie值，并将其返回
var token = getCookie("token");
var secret = parseInt(getCookie("secret"));     
if (token == "" || secret == "") {
    setTimeout("location=location; ", 3000)
}      //如果为空
else {
    var random = secret - 100;
    document.cookie = "token=; expires=Thu, 01 Jan 1970 00:00:00 UTC;";
    document.cookie = "secret=; expires=Thu, 01 Jan 1970 00:00:00 UTC;";
    document.cookie = "t=" + token + ";";
    document.cookie = "r=" + random + ";";
    window.location.reload(true)
}

证实上述猜想，获取cookies第二次请求得到正文内容。