Acwing 905. 区间选点
- 知识点
- 题目描述
- 思路讲解
- 代码展示
知识点
- 贪心
题目描述
思路讲解
代码展示
#include <iostream>
#include <algorithm>
using namespace std;
const int N = 1e5 + 10;
int n;
struct Range {
int l, r;
bool operator<(const Range &W) const {
return r < W.r;
}
} range[N];
int main() {
scanf("%d", &n);
for (int i = 0; i < n; i++) scanf("%d%d", &range[i].l, &range[i].r);
sort(range, range + n);
int res = 0, ed = -2e9;
for (int i = 0; i < n; i++)
if (range[i].l > ed) {
res++;
ed = range[i].r;
}
printf("%d\n", res);
return 0;
}