题目链接：多重背包问题 II

#include <iostream>
#include <algorithm>

using namespace std;

const int N = 12010, M = 2010;

int n, m;
int v[N], w[N];
int f[M];

int main()
{
    cin >> n >> m;
    
    // 最后一共转换成多少个物品
    int cnt = 0;
    for(int i = 1; i <= n; i ++)
    {
        int a, b, s;
        cin >> a >> b >> s;
        int k = 1;
        while(k <= s)
        {
            cnt ++;
            v[cnt] = a * k;
            w[cnt] = b * k;
            s -= k;
            k *= 2;
        }
        if(s > 0)
        {
            cnt ++;
            v[cnt] = a * s;
            w[cnt] = b * s;
        }
    }
    
    n = cnt;
    
    for(int i = 1; i <= n; i ++)
        for(int j = m; j >= v[i]; j --)
            f[j] = max(f[j], f[j - v[i]] + w[i]);
            
    cout << f[m] << endl;
    
    return 0;
}